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kkurt [141]
3 years ago
14

I need helppppp ughhhhhhh

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0
Wrong person I pay someone to do my math for me :)
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What is the solution for -x+10<4??
EleoNora [17]

Answer: x>6

Step-by-step explanation:

7 0
2 years ago
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What is the answer to the question Mx+2nx=p for x
Anni [7]
Undistribute x
x(m+2n)=p
divide both sides by m+2n
x=\frac{p}{m+2n}
4 0
3 years ago
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Please show your work !!!!!!!!!!!!
dedylja [7]

Answer:

(3.4)

Step-by-step explanation:

  • Our equation is f(x)=-2(x-3)^2+4
  • Now there are 2 ways you can do this, I'll show you the shortcut
  • If you have an equation like this, just take the value in parenthesis and equate it to zero
  • x-3=0.x=3 is the x of the vertex
  • Put this back into the equation
  • f(x)=-2(x-3)^2+4\\x=3\\f(3)=-2(3-3)^2+4\\f(3)=-2(0)^2+4=4 this is the y
3 0
2 years ago
If 90 is 80% of a value, what is that value?
Anna71 [15]
So 90 is 4/5 of a number.

4/5n=90

4n=450

n=450/4

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7 0
3 years ago
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Let f(x) = (x − 3)−2. find all values of c in (1, 4) such that f(4) − f(1) = f '(c)(4 − 1). (enter your answers as a comma-separ
Verizon [17]

If the function is (x-3)^{-2} and  f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.

Given function is (x-3)^{-2} and  f(4) − f(1) = f '(c)(4 − 1).

In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.

We begin by calculating f(2) and f(5):

f(2)=(2-3)^{-2}

f(2)=1

f(5)=(5-3)^{-2}

f(5)=1

And the slope of the function:

f^{1}(x)=f(5)-f(2)/(5-2)

f^{1}(c)=0

Now,

f^{1} (x)=-2*(x-3)^{-3}

=-2(x-3)^{-3}

=0

-2 is not equal to 0. So there is not any answer.

Hence if the function is (x-3)^{-2} and  f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.

Learn more about derivatives at brainly.com/question/23819325

#SPJ4

7 0
1 year ago
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