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3 years ago

Daily Dose of MEMES.

Mathematics

2 answers:

Zielflug [23.3K]3 years ago

7 0

Answer:

lol

Step-by-step explanation:

Lesechka [4]3 years ago

6 0

Answer:

one there is no milk in the fridge but you already poured the cereal

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I B.

Sliva [168]

Answer:

89 meters per second.

Step-by-step explanation:

That is quite fast!

First, we are given that in 9 sec our falcon has flown 801 meters, let's write an equation for that:

9s = 801

So in order to get s, we divide each side by 9.

Solve!

s = 801/9

s = 89

Happy learning! Please give a brainliest if you found this helpful

6 0

3 years ago

Learning Task 3. Find the equation of the line. Do it in your notebook.

Wewaii [24]

Answer:

1) The equation of the line in slope-intercept form is $y = 5\cdot x +9$ . The equation of the line in standard form is $-5\cdot x + y = 9$ .

2) The equation of the line in slope-intercept form is $y = \frac{2}{5}\cdot x +\frac{14}{5}$ . The equation of the line in standard form is $-2\cdot x +5\cdot y = 14$ .

3) The equation of the line in slope-intercept form is $y = 3\cdot x +4$ . The equation of the line in standard form is $-3\cdot x +y = 4$ .

4) The equation of the line in slope-intercept form is $y = 2\cdot x + 6$ . The equation of the line in standard form is $-2\cdot x +y = 6$ .

5) The equation of the line in slope-intercept form is $y = \frac{5}{6}\cdot x -\frac{7}{6}$ . The equation of the line in standard from is $-5\cdot x + 6\cdot y = -7$ .

Step-by-step explanation:

1) We begin with the slope-intercept form and substitute all known values and calculate the y-intercept: ( $m = 5$ , $x = -1$ , $y = 4$ )

$4 = (5)\cdot (-1)+b$

$4 = -5 +b$

$b = 9$

The equation of the line in slope-intercept form is $y = 5\cdot x +9$ .

Then, we obtain the standard form by algebraic handling:

$-5\cdot x + y = 9$

The equation of the line in standard form is $-5\cdot x + y = 9$ .

2) We begin with a system of linear equations based on the slope-intercept form: ( $x_{1} = 3$ , $y_{1} = 4$ , $x_{2} = -2$ , $y_{2} = 2$ )

$3\cdot m + b = 4$ (Eq. 1)

$-2\cdot m + b = 2$ (Eq. 2)

From (Eq. 1), we find that:

$b = 4-3\cdot m$

And by substituting on (Eq. 2), we conclude that slope of the equation of the line is:

$-2\cdot m +4-3\cdot m = 2$

$-5\cdot m = -2$

$m = \frac{2}{5}$

And from (Eq. 1) we find that the y-Intercept is:

$b=4-3\cdot \left(\frac{2}{5} \right)$

$b = 4-\frac{6}{5}$

$b = \frac{14}{5}$

The equation of the line in slope-intercept form is $y = \frac{2}{5}\cdot x +\frac{14}{5}$ .

Then, we obtain the standard form by algebraic handling:

$-\frac{2}{5}\cdot x +y = \frac{14}{5}$

$-2\cdot x +5\cdot y = 14$

The equation of the line in standard form is $-2\cdot x +5\cdot y = 14$ .

3) By using the slope-intercept form, we obtain the equation of the line by direct substitution: ( $m = 3$ , $b = 4$ )

$y = 3\cdot x +4$

The equation of the line in slope-intercept form is $y = 3\cdot x +4$ .

Then, we obtain the standard form by algebraic handling:

$-3\cdot x +y = 4$

The equation of the line in standard form is $-3\cdot x +y = 4$ .

4) We begin with a system of linear equations based on the slope-intercept form: ( $x_{1} = -3$ , $y_{1} = 0$ , $x_{2} = 0$ , $y_{2} = 6$ )

$-3\cdot m + b = 0$ (Eq. 3)

$b = 6$ (Eq. 4)

By applying (Eq. 4) on (Eq. 3), we find that the slope of the equation of the line is:

$-3\cdot m+6 = 0$

$3\cdot m = 6$

$m = 2$

The equation of the line in slope-intercept form is $y = 2\cdot x + 6$ .

Then, we obtain the standard form by algebraic handling:

$-2\cdot x +y = 6$

The equation of the line in standard form is $-2\cdot x +y = 6$ .

5) We begin with a system of linear equations based on the slope-intercept form: ( $x_{1} = -1$ , $y_{1} = -2$ , $x_{2} = 5$ , $y_{2} = 3$ )

$-m+b = -2$ (Eq. 5)

$5\cdot m +b = 3$ (Eq. 6)

From (Eq. 5), we find that:

$b = -2+m$

And by substituting on (Eq. 6), we conclude that slope of the equation of the line is:

$5\cdot m -2+m = 3$

$6\cdot m = 5$

$m = \frac{5}{6}$

And from (Eq. 5) we find that the y-Intercept is:

$b = -2+\frac{5}{6}$

$b = -\frac{7}{6}$

The equation of the line in slope-intercept form is $y = \frac{5}{6}\cdot x -\frac{7}{6}$ .

Then, we obtain the standard form by algebraic handling:

$-\frac{5}{6}\cdot x +y =-\frac{7}{6}$

$-5\cdot x + 6\cdot y = -7$

The equation of the line in standard from is $-5\cdot x + 6\cdot y = -7$ .

6 0

3 years ago

If f(x) = 2x - 5 , Find f(3). <br> Substitute 3 for x then type your final answer.

Savatey [412]

Answer:

f(3)=1

Step-by-step explanation:

take f(x)=2(x)-5

put a three wherever you see an x in parentheses

f(3)=2(3) - 5

simplify

f(3)=6-5

simplify

f(3)=1

answer:f(3)=1

5 0

3 years ago

Read 2 more answers

A fair coin is tossed three times.

qaws [65]

B 2/3
A 3/3. Hsheikdkekekekld

6 0

4 years ago

Read 2 more answers

This is the previous problem: A rabbit started at point 0 and made 3 jumps a jump of 4 units then a jump of 2 units and then a j

morpeh [17]

Answer:

Q1: The rabbit could be at eight different numbers of the number line: -7, - 5, - 3, - 1, 1, 3, 5, and 7.

Q2: 13

Step-by-step explanation:

Q1: Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:

Option 1: - 4 - 2 - 1 = -7

Option 2: - 4 - 2 + 1 = -5

Option 3: - 4 + 2 - 1 = - 3

Option 4: - 4 + 2 + 1 = - 1

Option 5: 4 - 2 - 1 = 1

Option 6: 4 - 2 + 1 = 3

Option 7: 4 + 2 - 1 = 5

Option 8: 4 + 2 + 1 = 7

Q2: If the rabbit started at 10 you would add 3 to 10 and get 13.

7 0

3 years ago