Answer:
0.00014
Step-by-step explanation:
The box contains a total of 24 + 33 + 35 = 92 jelly beans
If we need to pick 8 jelly beans and want them all to be green:
We can choose 8 green jelly beans from 33 green in C₃₃,₈ different ways
The total ways we can choose 8 jelly beans out from 92 is: C₉₂,₈
Thus, the probability we're looking for is C₃₃,₈ / C₉₂,₈ = 13884156/93080887185 =0.00014
Answer:
See explanation
Step-by-step explanation:
The question is incomplete, however, one of the requirements of this question while I searched, was to make a table and sketch the equation.
If this is the case, then, all you need to do is take the equation, Assume some values for x, and compute the values of y. Then, you can do the graph.
I begin with value from 0 to 10.
This is the example of calculations:
x = 0
y = 18.25*0 = 0
for x = 0, we get y = 0. For x = 2:
y = 18.25 * 2 = 36.5
If we keep doing this, we should get a straight line. See the graph and attached table. If the question is asking another thing, then please get back to me to answer it.
Answer:
The measure of the missing angle is 90°
Step-by-step explanation:
∵ This figure is a quadrilateral
∴ the sum of measures of its angles = 360°
∴ m∠x = 360 - 107 - 72 - 91 = 90°
Answer:
40 oz of sugar
Step-by-step explanation:
1) you have the basic measurement for 36 fluid ounces of lemonade, now imagine how many time can 36 go into 180 in order to find how many sugar oz you will need
180/36= 3
This mean 180 is 5 times as much lemonade and you will need 5 times as much sugar.
8ounces of sugar x 5 = 40ounces of sugar to make 180fluid ounces of lemonade
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614