Answer:
$48.72
Step-by-step explanation:
5.6 liters x $8.70 per liter= $48.72 total cost
<h3><u>Question:</u></h3>
A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula represents the volume of the pyramid?
<h3><u>Answer:</u></h3>
<em><u>The formula represents the volume of the pyramid is:</u></em>
<h3><u>Solution:</u></h3>
<em><u>The volume of square pyramid is given by formula:</u></em>
Where, "h" is the height of pyramid
"a" is the length of side of base
Here given that, pyramid has a square base with sides of length s
Therefore,
a = s
The height of the pyramid is equal to 1/2 of the length of a side on the base
<em><u>Thus the volume of pyramid becomes:</u></em>
Thus the formula represents the volume of the pyramid is
Answer:
12√5
Step-by-step explanation:
According to the attached sketch, there are 2 triangles which we need to focus on, triangle A (in yellow) and triangle B (In red).
If you look at triangle A, we notice that X is the hypotenuse of triangle A. This means that X must be the largest length in triangle A, hence we can say that x must be greater than 24 (or 24 < x)
Now look at triangle B, in this case, they hypotenuse is 30 and x is the length of one of the sides. This means that x must be shorter than the hypotenuse (i.e x < 30)
from the 2 paragraphs above, we can see now that we can assemble an inequality in x
24 < x < 30
If we look at the choices, we can immediately ignore 33 because x must be less than 30,
working out the choices, we find that the only choice which falls into the range 24<x<30 is the 2nd choice 12√5 (= 26.83) (which is the answer)
The last 2 choices give values smaller than 24 and are hence cannot be the answer
Answer:
Step-by-step explanation:
given D : (7,-3), and D' : (2,5)
the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).
you can simply take the difference in the x values and difference in the y values from the preimage to image.
like this:
f'(x,y) → f(x+(x-x1),y+(y-y1)) :
D'(x,y) → D(x+(2-7),y+(5--3))
D'(x,y) → D(x<u>-5</u>,y<u>+8</u>) :