Algebra 1 solve by elimination 6x-3y=30 6x+y=18
2 answers:
First, we need the coefficient of one of our variables to be the same.
In this case, it's already done for us. We have 6x in both equations.
Now, we just subtract the equations.
Note that the subtraction distributes to each term of that equation.
(you can also do something similar by adding equations--as long as you get rid of of that variable...and if your coefficients aren't the same to begin with, just multiply both sides of one of those equations to get them equal.)
Now, we just use that y = -3 to find x.
In this case, it's already done for us. We have 6x in both equations.
Now, we just subtract the equations.
Note that the subtraction distributes to each term of that equation.
(you can also do something similar by adding equations--as long as you get rid of of that variable...and if your coefficients aren't the same to begin with, just multiply both sides of one of those equations to get them equal.)
Now, we just use that y = -3 to find x.
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Answer:
Step-by-step explanation:
Hello!
We can use the difference of square method.
<h2>Difference Of Squares (DOS)</h2>The formula for the DOS is
It is a simple way to factor polynomials.
The criteria:
- Has to begin and end with a perfect square
- The operation has to be subtraction
Begins with a perfect square (x² * x²) and ends with a perfect square (4 * 4)
Warning! Watch out, there may be another DOS!
is another DOS
The x² + 4 is not a DOS because the operation is addition.
The final factored form is