Algebra 1 solve by elimination 6x-3y=30 6x+y=18
2 answers:
First, we need the coefficient of one of our variables to be the same.
In this case, it's already done for us. We have 6x in both equations.
Now, we just subtract the equations.
Note that the subtraction distributes to each term of that equation.
(you can also do something similar by adding equations--as long as you get rid of of that variable...and if your coefficients aren't the same to begin with, just multiply both sides of one of those equations to get them equal.)
Now, we just use that y = -3 to find x.
In this case, it's already done for us. We have 6x in both equations.
Now, we just subtract the equations.
Note that the subtraction distributes to each term of that equation.
(you can also do something similar by adding equations--as long as you get rid of of that variable...and if your coefficients aren't the same to begin with, just multiply both sides of one of those equations to get them equal.)
Now, we just use that y = -3 to find x.
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Answer:
Step-by-step explanation:
<u>Equation of a Circle</u>
A circle of radius r and centered on the point (h,k) can be expressed by the equation
We are given the equation of a circle as
Note we have corrected it by adding the square to the y. Simplify by 3
Complete squares and rearrange:
We can see that, if r=4, then
Or, equivalently
There are two solutions for :
Keeping the positive solution, as required: