Answer:
Step-by-step explanation:
Problem A
t(1) = 2(1) + 5
t(2) = 2*2 + 5 = 9
t(3) = 2*3 + 5 = 11
t(4) = 2*4 + 5 = 13
So this is the explicit result. Now try it recursively.
t_3 = t_2 + 2
t_3 = 9 + 2
t_3 = 11 which is just what it should do.
t_n = t_(n - 1) + 2
Problem B
t(1) = 3 * 1/2
t(1) = 3/2
t(2) = 3*(1/2)^2
t(2) = 3 * 1/4
t(2) = 3/4
t(3) = 3*(1/2)^3
t(3) = 3 * 1/8
t(3) = 3/8
t(4) = 3 (1/2)^4
t(4) = 3 (1/16)
t(4) = 3/16
So in general
t_n = t_n-1 * 1/2
For example t(5)
t_5 = t_4 * 1/2
t_5 = 3 /16 * 1/2 = 3/32
Answer:
Revolutions=37079108.61 rev
Step-by-step explanation:
First if all we have to make the units same to calculate the revolutions
Since distance gis gien in km and radius is given in m we will covert distance to m first.
Distance =S=65000km
Distance=S=65000km*1000m/km
Distance = S= 65000000m
Formula:
S=rθ
where
S is the distance
r is the radius
θ is the revolution in radian
θ=S/r
θ=65000000/0.279
θ=232974910.4 rad
Revolutions=θ/2π
Revolutions=232974910.4/2π
Revolutions=37079108.61 rev
R mean radius and d mean diameter so C mean circumference ? please clearifie these - thank you
Answer:
x=50 ∠BCX=65
Step-by-step explanation:
The angles is a triangle add up to 180 so
70+45+∠BCX=180 so
115+∠BCX=180 (subtract 115 from both sides)
∠BCX=65
A line adds up to 180
so 2x+15+65=180
so 2x+80=180 (subtract 80 from both sides)
2x=100 (divide by 2)
x=50
