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Kazeer [188]
3 years ago
8

Assuming that the drug has no​ effect, so that the probability of nausea was 0.0124​, find the mean and standard deviation for t

he numbers of people in groups of 828 that can be expected to experience nausea.
Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer:

11.

Step-by-step explanation:

Given that the drug has no effect and that the probability of nausea was 0.0124, to find the mean and standard deviation for the numbers of people in groups of 828 that can be expected to experience nausea, the following calculation must be performed:

828 x 0.0124 = X

10.26 = X

Thus, the number of people who may feel nauseous after using the drug in question is 11 individuals.

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Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

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