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Mandarinka [93]
3 years ago
6

Find all zeros.

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

look at degree of polynomial

Step-by-step explanation:

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81, 6, 7, 1, 42<br> Mode ??<br> Median ??
seraphim [82]

Answer:

No mode

Median 7

Step-by-step explanation:

Mode: The mode is the element that occurs most in the data set. In this case, all elements occur only once, so there is no mode.

Median: Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers.

8 0
3 years ago
Read 2 more answers
write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)
dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is y - 3 = \frac{-7x}{2}+ \frac{21}{4}

<h3><u>Solution:</u></h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

<em><u>The slope "m" of the line is given as:</u></em>

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Here the given points are A(-2,2) and B(5,4)

\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4

m=\frac{4-2}{5-(-2)}=\frac{2}{7}

Thus the slope of line with given points is \frac{2}{7}

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}

The perpendicular bisector will run through the midpoint  of the given points

So let us find the midpoint of A(-2,2) and B(5,4)

<em><u>The midpoint formula for given two points is given as:</u></em>

\text {For two points }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right), \text { midpoint } \mathrm{m}(x, y) \text { is given as }

m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Substituting the given points A(-2,2) and B(5,4)

m(x, y)=\left(\frac{-2+5}{2}, \frac{2+4}{2}\right)=\left(\frac{3}{2}, 3\right)

Now let us find the equation of perpendicular bisector in point slope form

The perpendicular bisector passes through points (3/2, 3) and slope -7/2

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x - x_1)

\text { Substitute } \mathrm{m}=\frac{-7}{2} \text { and }\left(x_{1}, y_{1}\right)=\left(\frac{3}{2}, 3\right)

y - 3 = \frac{-7}{2}(x - \frac{3}{2})\\\\y - 3 = \frac{-7x}{2}+ \frac{21}{4}

Thus the equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is found out

7 0
4 years ago
At a bargain store, Spongebob bought 3 items that each cost the same amount. Patrick bought 5 items that each cost the same amou
STALIN [3.7K]

Answer:

Cost of each item bought by Spongebob =x=\$3.75

Cost of items bought by Spongebob = 3x=3(3.75)=\$11.25

Cost of each item bought by Patrick =x-1.50=3.75-1.50=\$2.25

Cost of items bought by Patrick = 5(x-1.50)=5(3.75-1.50)=\$11.25

Step-by-step explanation:

Let x denotes cost of each item bought by Spongebob.

Number of items bought by Spongebob = 3

So,

Cost of items bought by Spongebob = 3x

Cost of each item bought by Patrick = x-1.50

Number of items bought by Patrick = 5

Cost of items bought by Patrick = 5(x-1.50)

Both Spongebob and Patrick paid the same amount of money.

So,

3x=5(x-1.50)\\3x=5x-7.5\\5x-3x=7.5\\2x=7.5\\x=\frac{7.5}{2} \\x=3.75

So,

Cost of each item bought by Spongebob =x=\$3.75

Cost of items bought by Spongebob = 3x=3(3.75)=\$11.25

Cost of each item bought by Patrick =x-1.50=3.75-1.50=\$2.25

Cost of items bought by Patrick = 5(x-1.50)=5(3.75-1.50)=\$11.25

6 0
3 years ago
- 4/5 divided by 7/8
Andru [333]

Answer:

-32/35

Step-by-step explanation:

-4/5 *8/7 you have to flip the right fraction to multiply since you cant actually divide

hope this helps

8 0
3 years ago
Can a cross-section be a sphere?
Gelneren [198K]
No because spheres are not polyhedra
8 0
4 years ago
Read 2 more answers
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