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2 years ago

Please help due in 10 min will mark brainliest

Mathematics

1 answer:

nlexa [21]2 years ago

7 0

Answer:

Option D will be your answer

<u>------------------------------------------</u>

<u>hope it helps..</u>

<u>have a great day!!</u>

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Solve: 4|x| = 32 a 8 b –8 or 8 c 24 d No solution

anyanavicka [17]

x= -8 , 8

your answer

b –8 or 8

4 0

3 years ago

1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the

ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

$v_1 = 60\ mph$

Sheyna drives back from the lake with average speed of 36 mph

$v_2 = 36\ mph$

It took 2 hours less time to get there than it did to get back.

Let $t_1$ be the time taken to drive to lake.

Let $t_2$ be the time taken to drive back from lake.

$t_2-t_1 = 2$ hrs ..... (1)

To find:

Total time taken = ?

$t_1+t_2 = ?$

Solution:

Let D be the distance to lake.

Formula for time is given as:

$Time =\dfrac{Distance}{Speed }$

$t_1 = \dfrac{D}{60}\ hrs$

$t_2 = \dfrac{D}{36}\ hrs$

Putting in equation (1):

$\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles$

So,

$t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs$

$t_2 = \dfrac{180}{36}\ hrs = 5\ hrs$

So, the answer is:

$t_1+t_2 = \bold{8\ hrs}$

8 0

3 years ago

Help. rhombus JKLM is shown below. Find m<KLM

pantera1 [17]

Answer: It's 76 (sorry, I answered it wrong!)

Step-by-step explanation:

In a rhombus, the diagonals split the angles into two equal parts. If one part of the angle is 38, then the other part is 38. Add up both of them, and you'll get the entirety of angle L, which is 76.

6 0

3 years ago

Pls help me I’m not that smart at fractions

salantis [7]

Answer:

Step-by-step explanation:

5/8

you need to add all numerators, same denominator

5 0

3 years ago

Read 2 more answers

A metalworker has a metal alloy that is 20% copper and another alloy that is 60% copper. How many kilograms of each alloy shou

puteri [66]

<h3>Answer:</h3>

<u>20</u> kg of 20%
<u>80</u> kg of 60%

<h3>Step-by-step explanation:</h3>

I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.

That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.

_____

<em>Using an equation</em>

If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...

... 0.60x + 0.20(100 -x) = 0.52·100

... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20

... x = 32/0.40 = 80 . . . . . kg of 60% alloy

... (100 -80) = 20 . . . . . . . .kg of 20% alloy

6 0

3 years ago