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Shkiper50 [21]
3 years ago
15

A 6-foot ladder touches the side of a building at a point 5 feet above the ground. At what height would a 18-foot ladder touch t

he building if it makes the same angle with the ground as the shorter ladder?
Mathematics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

15 feet above the ground

Step-by-step explanation:

We know sinθ = opposite/hypotenuse where h = height of the ladder above the ground = opposite = 5ft and L = length of ladder = hypotenuse side = 6 feet. sinθ = h/L

For the new ladder to make the same angle, sinθ must be the same, so let h' = height of new ladder above the ground and L' = length of new ladder = 18 ft

sinθ = h'/L'

So. h'/L' = h/L

h' = hL'/L

substituting the values of the variables, we have

h' = 5 ft × 18 ft/6 ft

= 5 ft × 3

= 15 ft

So, the 18-foot ladder must be placed 15 feet above the ground to make the same angle as the smaller ladder.

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i made a video explaining its on

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Nisha collects comic books, and she convinced her friend Hakim to start collecting as well. Every week, they go to the store tog
andreyandreev [35.5K]

By using the given table, we will get the linear equation:

h = n - 9

<h3>How to find the equation for Hakim?</h3>

We know that they always get comic books together, so always that Nisha's collection increases by one, Hakim's collection will also increase by one, so we will have a linear equation.

Now, if you look at the given table, you can see that Hakim's collection is always 9 units less than Nisha's collection, then the linear equation that models the relation between the two collections, h and n, is really straightforward, it will be:

Hakim's collection = Nisha's collection - 9

Using the variables, we get:

h = n - 9

That is the linear equation Hakim wanted.

If you want to learn more about linear equations:

brainly.com/question/1884491

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1 year ago
Choose the amount of money that is equal to 9 dimes. 4 quarters 3 quarters 3 nickels 2 quarters 3 dimes 4 quarters
mixas84 [53]

Answer:

$4.60 dollars

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3 years ago
Giving thanks and brainliest for best answer &lt;3
UNO [17]
The answer is D 80-99
4 0
3 years ago
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A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

16 = 4r^2 + h^2

16 - 4r^2 = h^2

\implies h=\sqrt{16-4r^2}

Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

Differentiating with respect to r,

\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})

=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})

Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

For maximum or minimum,

\frac{dS}{dt}=0

2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0

-8r^2 + 16 = 0

8r^2 = 16

r^2 = 2

\implies r = \sqrt{2}

Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

4 0
3 years ago
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