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stellarik [79]
3 years ago
12

What is the prime factorization of 48?

Mathematics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

b

Step-by-step explanation:

B is the most simplified, because 2 times itself 4 times equals 16, 16 times 3 is 48. all numbers are down to their most simplified form

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Leslie tunes a guitar with 6 strings and a piano with 37 times as many strings.
Nataly [62]
B 37*6 = 222.
Multiply 6*7 = 42
Multiply 3*6 =18 + 4 = 22

37
*6
222

5 0
3 years ago
PLEASE HELP ME ASAP!!!!
kirill115 [55]

Answer:

y=  5x + 3

Step-by-step explanation:

This is because you solve for slope, which is 5, then plug that into point slope form to get:

y - 8 = 5(x - 1)

y - 8 = 5x - 5

y = 5x  + 3.

6 0
3 years ago
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Carlos walked to school on 14 of the 20 school days in February. Which value is equivalent to the fraction of the school days in
Leto [7]

Answer: A

Step-by-step explanation: 14/20 = 70%

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3 years ago
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What is the vertex of a parabola defined by the equation <br> x = 5y2?
QveST [7]

Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0

3 0
3 years ago
HELP PLEASE!
olasank [31]

Answer        

Find out the Area of a triangle .

To proof  

Formula

Area of Triangle

= \frac{1}{2}\times( {x_1(y_{2}-y_{3}) +x_{2}(y_{3} - y_{1})+x_{3}(y_{1}-y_{2})})

Now vertices are D(3, 3) , E(3, −1) , and F(−2, −5) .

= \frac{1}{2} (3\times(-1 +5) + 3\times(-5-3)-2\times(3+1))

Solving the above

= \frac{1}{2}(3\times4+3\times-8 -2\times4)

=\frac{1}{2} (12-24-8)\\ =\frac{1}{2} (-32+12)\\=\frac{1}{2} (-20)

= -10 units²

(Neglected the negative sign as area cannot be negative.)

= 10 units ²

Area of  a triangle is 10 units ²

Hence proved

6 0
3 years ago
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