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2 years ago

PLEASE HELP ASAP!!!!!!

Mathematics

2 answers:

IRINA_888 [86]2 years ago

7 0

Negative, this is because it goes downwards left meaning it’s negative. Also the points aren’t very close together.

horsena [70]2 years ago

3 0

Answer:

it is negative bc it runs down when it runs up it is positive

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kondor19780726 [428]

24 is what i believe the answer is

3 0

3 years ago

I NEED HELP PLEASE!!!

solmaris [256]

Answer:

Step-by-step explanation:

cos(theta) is positive in IV quadrant and sin(theta)=sqrt(13^2-5^2)/13=-12/13

7 0

2 years ago

D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

2x + 10 3x - 18

2x + 10 = 3x - 18

2x - 3x = -18 - 10

-x = -28

x = 28

CE = 2x + 10 + 3x - 18

CE = 2(28) + 10 + 3(28) - 18

CE = 56 + 10 + 84 - 18

CE = 132

3 0

3 years ago

A garden in the shape of a right triangle is bordered on one side by a brick wall, on another side by a wooden fence, and on the

MAVERICK [17]

Let
x-----> the measure of the angle formed by the wooden fence and grass

we know that
in a right triangle
tan x=opposite side angle x/adjacent side angle x
opposite side angle x=13 ft
adjacent side angle x=21 ft
so
tan x=13/21x=arc tan (13/21)-----> x=31.76°------> x=32°

the answer is
32 degrees

3 0

3 years ago

Read 2 more answers

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span> $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago