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Rzqust [24]
3 years ago
14

The cost for a company to produce x t-shirts can be modeled by C(x)=21x-98 and the revenue for selling these shirts can be model

ed by r(x)=55x-2^2. Which function represents the company's total profit after selling x shirts?
A. P(x)=2x^2-34x+98
B. P(x)=-2x^2-34x+98
C. P(x)=-2x^2+34x+98
D. P(x)=2x^2+34x-98
Mathematics
2 answers:
shusha [124]3 years ago
8 0

Answer:

P(x)=-2x^2+34x+98

Step-by-step explanation:

The cost function is given by c(x)=21x-98

And the revenue function is given by  r(x)=55x-2x^2

The profit function is the difference of revenue function and the cost function. Mathematically, we can write

P(x)=r(x)-c(x)

Substituting the values, we get

P(x)=55x-2x^2-(21x-98)\\\\P(x)=-2x^2+34x+98

Therefore, the profit function is

P(x)=-2x^2+34x+98

C is the correct option.

mixer [17]3 years ago
5 0

Answer:

The Answer is C

Step-by-step explanation:

It's C for Apex

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B

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15% of the parking spaces at a school are reserved. The school has 12 reserved spaces. How many parking spaces are there in tota
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Answer: 76

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2 years ago
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The pie chart represents the proportions of how Henry spent the £720 he took on holiday.
Oksana_A [137]

Answer:

£124

Step-by-step explanation:

first of all, you're meant to add all the figures given on the pie chart, which is 29+137+58+62+74 and that will give you a total of 360 degrees

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2 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

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The fraction is 15/20 and the fraction of chocolate cookies is 4/20
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