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Bas_tet [7]
2 years ago
9

Sheila needs to hire a baby sitter for the evening.

Mathematics
1 answer:
marissa [1.9K]2 years ago
5 0

Answer: The answer is 21

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Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of
serious [3.7K]

Answer:

i(x)=12 \times (1+\frac{0.9}{12})^{12x} and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 \times (1.9)^{x}, where x is the number of years.

Since, i(x)=12 \times (1.9)^{x}

i.e. i(x)=12 \times (1+0.9)^{x}.

Therefore, the monthly growth rate function becomes,

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}.

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Hence, the monthly growth rate is i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Also, the growth factor is given by \frac{0.9}{12} = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

4 0
3 years ago
Use the table to determine the location with the greatest amount of rainfall and the location with the least amount of rainfall.
Kryger [21]

Step-by-step explanation:

I think it is hilo hawii 480 cm it has the longest cm

7 0
2 years ago
Simplify the expression 7t +3- 2 t
Ivenika [448]

Answer:

5t+3

Step-by-step explanation:

1 Collect like terms.

(7t-2t)+3

2 Simplify.

5t+3

7 0
1 year ago
Read 2 more answers
Casey bought a 15.4 pound turkey and an 11.6 pound ham for Thanksgiving and paid $38.51.
White raven [17]

Answer:

h =  1.74

t =  1.19

Step-by-step explanation:

15.4t + 11.6h = 38.51

10.2t + 7.3h = 24.84

15.4•t + 11.6•h = 38.51

10.2•t + 7.3•h = 24.84

11.6h+15.4t = 38.51

7.3h+10.2t = 24.84

h = 87

50

= 1.74

t = 119

100

= 1.19

6 0
2 years ago
How much will $850 amount to be in three years if it is invested at 8% interest compounded quarterly for 3 years? A. $886.47 B.
Dimas [21]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$850\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, so four times}
\end{array}\to &4\\

t=years\to &3
\end{cases}
7 0
3 years ago
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