Question

Complete the squares 6+4x-x^2

Answer 1

$\text{Hey there!}$

$\text{Use the quadratic formula to solve this!}$

$\mathsf{Formula: ax^2+bx+c=0}$

$\mathsf{ax^2=x^2}\\\mathsf{bx=4x}\\\mathsf{c=6}\\\mathsf{0=0}$

$\rightarrow\ =\mathsf{-1x^2+4x+6=0}$

$\bf{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\leftarrow \ \mathsf{The\ other\ formula}$

$\bf{x= \dfrac{(-4)\pm\sqrt{(4)^2-4(-1)(6)}}{2(-1)}}$

$\mathsf{(4)^2-4(-1)(6)}\\\mathsf{4^2=16}\\\mathsf{16-4(-1)(6)}\\\mathsf{4(-1)=-4}\\\mathsf{16-(-4)(6)}\\\mathsf{-4(6)=-24}\\\mathsf{16-(-24)=16+24}\\\mathsf{=40}$

$\mathsf{2(-1)=-2}$

$\mathsf{x=\dfrac{-4\pm\sqrt{40}}{-2}}$

$\mathsf{\sqrt{40}\ =\ 2\sqrt{10}}}$

$\huge\text{\bf{SOLVE that above and you have your}}}\\\huge\text{\bf{ANSWER}}$

$\boxed{\boxed{\bf{Answer: x=2-\sqrt{10}\ or\ x=2+2\sqrt{10}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

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