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Iteru [2.4K]
3 years ago
14

4 x 105 in standard notation

Mathematics
1 answer:
Paul [167]3 years ago
6 0

Answer:

Lol its 420

Step-by-step explanation:

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I use 3 fifth size strips to model 3/5.I want to use tenth size strips to model an equivalent fraction.How many tenth size strip
Yuri [45]
3/5= 3 fifth size strips
You want to find an equivalent fraction with the denominator of ten, correct? Then you would multiply the fraction in a way that will allow you to have a denominator of ten.
So...
3/5*2/2=6/10
You would need 6 tenth size strips.
5 0
3 years ago
I have475 pounds of Apples to make1000 apple tarts how many pounds of apples are in each tart
olga nikolaevna [1]

Answer:

2.2 lbs

Step-by-step explanation:

1000/475

4 0
3 years ago
What is 8.786 rounded to nearest tenth
pentagon [3]
8.8 because .78 rounded up is .8
4 0
3 years ago
Read 2 more answers
Plz help<br>urgent !!!!<br>will give the brainliest !!​
Mkey [24]

Answer:

X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}

Step-by-step explanation:

The question we have at hand is, in other words,

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix} - where we have to solve for the value of X

If we have to isolate X here, then we would have to take the inverse of the following matrix ...

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix} ... so that it should be as follows ... \begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}

Therefore, we can conclude that the equation as to solve for " X " will be the following,

X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} - First find the 2 x 2 matrix inverse of the first portion,

\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}= \frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} ,

X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix} - Simplifying this, we should get ...

\begin{bmatrix}1&3\\ 2&4\end{bmatrix} ... which is our solution.

7 0
3 years ago
Solve x≤0 and x≥−4 and write the solution in interval notation. If there is no solution, type ∅.
xxTIMURxx [149]

The answer is (-∞.∞).

Draw out a number line. Plot 0 and -4 on the number line.

Shade to the left of x = 0, and have a filled in circle at the endpoint. This is the graph of x≤0

Then graph x ≥−4 by plotting a filled in circle at -4, and shading to the right.

Note how the two graphs overlap to cover the entire real number line

So if we have x≤0  or  x≥−4 then we're basically saying x is any real number. To write this in interval notation, we write (−∞,∞)

This is the interval from negative infinity to positive infinity (or just infinity). We exclude each endpoint because we can't actually reach infinity itself. Infinity is not a number. Infinity is a concept

Side note: if you change the "or" to "and", then the solution to x≤0  and  x≥−4 would be [-4, 0][−4,0] to indicate the interval from x = -4 to x = 0, including both endpoints. This is the region where the two graphs overlap.

To know more about graphs

visit-:brainly.com/question/10712002

SPJ9

5 0
2 years ago
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