Odd integers would include: -1, 1, and 3.
<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:$303,480
Step-by-step explanation: with excellent credit which is $843 per month for 30 years. So first I did 12 x 30 = 360 since there are 360 months in 30 years. And then 843 x 360 = $303,480. So $303,480 is your answer
