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olga2289 [7]
3 years ago
8

Given the geometric sequence where a1 = 2 and r = √2 find a9 32 32√2 256 256√2

Mathematics
2 answers:
stellarik [79]3 years ago
5 0

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

There is a geometric sequence:

where a₁ = 2

r = √2

We need to find a₉:

As we know the formula for "nth term ":

a_n=ar^{n-1}\\\\a_9=ar^{9-1}\\\\a_9=ar^8\\\\a_9=2\times (\sqrt{2})^8\\\\a_9=32

Hence, First option is correct.

pentagon [3]3 years ago
4 0
A9=a1*r^8

a9= 2*V2^8=2*2^4=2^5

⇒ a9 = 32
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The average of eight numbers is 56. When one of the numbers was left out, the mean decreased to 54. What number was left out?
lozanna [386]

Step-by-step explanation:

Given the average of 8 numbers = 56.

Then the Total sum of 8 numbers = 56 * 8

                                                        = 448.

Sum of 1st three numbers = 49 + 57 + 72

                                           = 178.

So, the total = 448 - 178

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