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omeli [17]
3 years ago
12

I need help please and thanks

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

SAS

Step-by-step explanation:

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Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the fiv
Nesterboy [21]

Answer:

a) It is probability distribution

b) mean = 2.5

c) Standard Deviation = 1.11

Step-by-step explanation:

We are given the following in the question:

x          0           1           2         3          4          5

P(x)  0.033   0.149   0.318   0.318   0.149   0.033

Probability distribution:

\displaystyle\sum P_i(x_i) = 0.033+ 0.149 +0.318+ 0.318+ 0.149 +0.033 = 1

Since, the summation of all the probabilities is 1 and each value of probability is between 0 and 1, the given is a probability distribution.

Mean of probability distribution:

E(x) = \displaystyle\sumx_iP(x_i)\\E(x) = 0(0.033)+ 1(0.149)+2(0.318)+3(0.318) +4(0.149) + 5(0.033)\\E(x) = 2.5

Thus, the mean of distribution is 2.5

Standard deviation of probability distribution:

E(x^2) = 0^2(0.033)+ 1^2(0.149)+2^2(0.318)+3^2(0.318) +4^2(0.149) + 5^2(0.033)\\E(x^2) = 7.492\\\sigma^2 = E(x^2) - (E(x))^2\\\sigma^2 = 7.492 - (2.5)^2 = 1.242\\\sigma= \sqrt{1.242} = 1.11

Thus, the standard deviation of the probability distribution is 1.11

5 0
4 years ago
What, if anything, is wrong with the frequency table for this data?
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It's C I took the quiz

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Step-by-step explanation:

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