Answer:
30
Step-by-step explanation:
120+30 =150
180-150 =30
First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt, Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h
so the ship will be on the radar at 2.1h,
Answer:
32h^7
Step-by-step explanation:
(4h^4)3=64h^12
64h^12/2h^5=
32h^12/2h^5=32h^7
Hope this helps :)
Hello,
John : n
Brad : n + 12
n + n + 12 = 84
2n + 12 = 84
2n = 84 - 12
2n = 72
n = 72/2
n = 36
John $36 and Brad $36 + $12 = $48
