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Licemer1 [7]
3 years ago
8

10 meters wide with a surface area of 80 square meters. ​

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

Answer:

8

Step-by-step explanation:

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Find the area of a rectangle with side lengths 5 8 ft. and 1 3 ft. Use the drawing to help you solve the problem. A 1-foot by 1-
Alex

Answer:

D. 5/24 ft²

Step-by-step explanation:

A = LW

A = 5/8 ft × 1/3 ft

A = 5/24 ft²

5 0
2 years ago
14 less than 8 times a number is 3 more than 4 times the number. What is the number? ​
e-lub [12.9K]

Answer:

x = 17/4

Step-by-step explanation:

Let x = the number

8x-14 = 4x+3

Subtract 4x from each side

8x -14-4x = 4x+3-4x

4x-14 = 3

Add 14 to each side

4x-14+14 = 3+14

4x = 17

Divide by 4

4x/4 = 17/4

x = 17/4

8 0
2 years ago
A 4-foot tall person standing with her back to the sun casts an 6-foot long shadow.
e-lub [12.9K]

Answer:  \alpha=34\°

Step-by-step explanation:

1. Based on the information given in the problem, you can draw the right triangle shown in the figure attached.

2. Keeping the informationn given in the problem, you can calculate the angle that the sum makes with the ground (\alpha)as you can see below:

arctan\alpha=\frac{opposite}{adjacent}

Where:

opposite=4\\adjacent=6

3. Then:

 arctan\alpha=\frac{4}{6}

\alpha=34\°

7 0
3 years ago
Read 2 more answers
Please help! <br> -<br> -<br> -<br> -<br> -
Jlenok [28]
The answer has to be in y-intercept form. Which is y=mx+b and b can also be neg. y=mx-b. The m is your slope and b is your y-intercept. So A’s slope counting from 3 on the y axis to 1 on the x-axis which is down 2 over 1 so it will be -2/1. And your y intercept is 3. The equation is y=-2x+3. For B its the same thing but no graph. Remember that slope is RISE over RUN. So since the number is on the bottom of the line the rise is 4 and the run is 1. So in this case 10 is your y-intercept. Which means you equation is y=4x+10.

5 0
2 years ago
Solve using elimination.<br> 2x – 3y = -7<br> -8x + 3y = 19
Brums [2.3K]

Answer:

-2,1

Step-by-step explanation:

5 0
3 years ago
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