Due immediately!!!!! Please help!!!

X/3+9=17 simplify your answer

frosja888 [35]

I think the answer might be x=24

8 0

3 years ago

Find the perimeter of ABCD<br> Find the area of Area

san4es73 [151]

Step-by-step explanation:

A = (1, 3)

B = (3, 6)

C = (9, 2)

D = (7, -1)

the distance between 2 points is given by the Pythagoras equation based on the coordinate differences as legs of virtual right-angled triangles.

AD for example we get from

AD² = (7-1)² + (-1 - 3)² = 6² + (-4)² = 36 + 16 = 52

AD = sqrt(52) = sqrt(4×13) = 2×sqrt(13)

and AB we get from

AB² = (3-1)² + (6-3)² = 2² + 3² = 4 + 9 = 13

AB = sqrt(13)

the perimeter of the given rectangle is

2×sqrt(52) + 2×sqrt(13) = 2×2×sqrt(13) + 2×sqrt(13) =

= 6×sqrt(13) = 21.63330765...

and the area of the rectangle is

2×sqrt(13)×sqrt(13) = 2×13 = 26

7 0

2 years ago

Write an equation in point slope form for a line that includes the origin and (9,-3)

aivan3 [116]

So we are given two points that the line crosses, the origin and (9, -3), we can calculate the slope m of the line with these data, dividing the y segment by the x segment:
m = (-3 - 0)/(9 - 0) = -3/9
m = -1/3
then we can use the point slope line equation to find the line equation, lets use the point origin (0,0) to do so:
y - y1 = m(x - x1), where x1, y1 are the coordinates of a point that the line crosses:
y - 0 = (-1/3)(x - 0)
y = <span>(-1/3)x
so this is the equation of the line, slope -1/3 and y intercept 0</span>

3 0

3 years ago

PLZ HELP I WILL MARK BRAILNLEIST!! 20. b) Find the side length of the square. [No label is required.] *

iogann1982 [59]

Answer:

The length of one side is 13 feet.

Step-by-step explanation:

To start, a square is 4 sides that are equal in length. This means that when you have a problem like this, you need to set the equations equal to each other like:

$2x+5=6x-11$

In order to solve a problem like this, with the same variables on different sides, start by subtracting the smaller variable from both sides. In this case, you would be subtracting 2x from both sides, which would leave us with:

$5=4x-11$

After that, you solve it like a normal one-step equation. Add 11 to both sides.

$16=4x$

Now, divide both sides by 4 and you will know how much $x$ is worth.

$4=x$

Now that we know how much $x$ is worth, we can plug that into either of the equations given to us. It doesn't matter which since they are equal to each other.

$2(4)+5$

That would give us 13.

5 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

So

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

So

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

So

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$

Coming back to x:

We have that:

$x = 3\sin{\theta}$

So

$\sin{\theta} = \frac{x}{3}$

Applying the arcsine(inverse sine) function to both sides, we get that:

$\theta = \arcsin{(\frac{x}{3})}$

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

8 0

3 years ago