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3 years ago

What is the prime factor of 236

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

Step-by-step explanation:

prime factorization calculator of 326

Positive Integer factors of 326 = 2, 163, 326 divided by 2, 163, gives no remainder. They are integers and prime numbers of 326, they are also called composite number.

326 is a composite number.

Prime factorization: 326 = 2 x 163.

The exponents in the prime factorization are 1 and 1. ...

Factors of 326: 1, 2, 163, 326.

Factor pairs: 326 = 1 x 326 or 2 x 163.

326 has no square factors that allow its square root to be simplified.

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The third graders collected 754 cans the fourth graders collected 592 cans estimate how many more cans the third graders collect

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754 minus 592 is 162 so estimated to the tens would be 160.

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Find the value of x. Round to the nearest tenth.

Helga [31]

Answer:

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Step-by-step explanation:

Angle ∠A = 41.124° = 41°7'26" = 0.71775 rad

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3 years ago

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

18 values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above 18 values for n are possible.

3 0

3 years ago

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goldfiish [28.3K]

Answer:

Step-by-step explanation:

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4 0

3 years ago

What is the prime factor of 236​

What is the prime factor of 236