Answer: The large ____ holds 48 units.
For the diagram you could draw the small rectangle 4 squares wide and 9 squares long. that will represent something that holds 36 units.
For the large one make it 4 squares wide and 12 squares long. That will have spaces for 48 units.
Step-by-step explanation: Change the percent to a decimal and set up the equation that means 36 is 75% of some number, yet unknown, X is the unknown number.
36 = .75x divide both sides by .75
36/.75 = .75x/.75 . The .75 "cancels" on the right. Then use a calculator.
36 ÷ .75 = 48
x = 48
The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Answer:
a,480 over 60=80cm3
b,(c over 24)the whole cubed=480 over 60
c*60=24*480
c=11520/60
=192
Answer:

Step-by-step explanation:
In order to find the side mentioned (IJ), we need to use SOH CAH TOA.
SOH CAH TOA is an acronym to help us remember what sin, cos, and tan mean. It stands for:
Sin = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tan = Opposite / Adjacent
Since we know the measure of angle K (42) and we know one of the sides, we can use this to find the missing length.
Since the side given to us is the hypotenuse, and we're looking for the side opposite of the angle (IJ), the only possible one to use would be SIN as it includes Opposite and Hypotenuse.
Our equation is now this: 
Let's now solve for x.
Therefore, the length of IJ will be around 2.01.
Hope this helped!