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pogonyaev
3 years ago
7

I need help with the equation inserted in the picture.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

x = 4

-4x+21 => 5

Step-by-step explanation:

The given triangle in the picture is isosceles triangle which means that two sides of the triangle are equal.

So,

Side\ 1: -4x+21\\Side\ 2: -4x+21\\Side\ 3: 6\\Perimeter = 16

Now

Putting all the values in equation for perimeter

Side\ 1+Side\ 2+Side\ 3 = 16\\-4x+21 -4x+21 + 6 =16\\-8x +48 = 16\\-8x = 16-48\\-8x = -32\\\frac{-8x}{-8} = \frac{-32}{-8}\\x = 4

Putting x = 4 in side 1

=-4(4)+21\\= -16+21\\=5

Hence,

x = 4

-4x+21 => 5

You might be interested in
Complete the table of values fory=2x^2+x
Semmy [17]

Complete question:

y = 2x² + 2x - 3

x = -2 -1 0 1 2

Answer:

<u>Complete table of values</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

Step-by-step explanation:

Given;

y = 2x² + 2x - 3

To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.

when, x = -2

y = 2(-2)² + 2(-2) - 3

y = 8 - 4 - 3

y = 1

when x = -1

y = 2(-1)² + 2(-1) - 3

y = 2 - 2 - 3

y = -3

when x = 0

y = 2(0)² + 2(0) - 3

y = 0 - 0 - 3

y = -3

when x = 1

y = 2(1)² + 2(1) - 3

y = 2 + 2 - 3

y = 1

when x = 2

y = 2(2)² + 2(2) - 3

y = 8 + 4 - 3

y = 9

<u>Complete table</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

7 0
3 years ago
How to constructed a square polygon
pogonyaev

Answer:

Construct a square of side length 4 cm

Step-by-step explanation:

* Lets explain how to construct a square polygon with side length 4 cm

- Use your straightedge to draw a horizontal line

- Measure on the horizontal line a segment of 4 cm

- Label its endpoints by A and B (AB = 4 cm)

- Open your compass at a distance greater then half AB (3 cm)

- Put the pin of the compass at point B and draw an arc intersects AB

 at point E and the horizontal line at point F

- Open the compass at a distance greater than the length of the side

 of the square (6 cm) and put its pin on the point E and draw an arc

- Put the pin of the compass on the point F without changing the open

 of the compass and draw another arc

- The two arcs intersect each other at point G

- Join BG and measure 4 cm from point B and label the end point of

 the 4 cm by C

- Open your compass at a distance 4 cm and put the pin on point C

 and draw an arc and put it on point A with the same distance 4 cm

 and draw another arc, the two arc intersect each other at point D

∴ ABCD is a square of side length 4 cm

# Look to the attached figure to more understand

5 0
3 years ago
I need all I don't know how to do????
Ghella [55]
Need the answers to all the questions?

6 0
3 years ago
How would I figure this out?? pls explain.
NeX [460]

Answer:

D

Step-by-step explanation:

The diagonals of a rhombus bisect the angles, thus

∠ ABC = ∠ CBD = 5x - 18 and

∠ BAC = ∠ DAC = x

The diagonals are perpendicular bisectors of each other, thus

the angles round the intersection of the diagonals = 90°

Consider the triangle on the left of the rhombus, then

5x - 18 + x + 90 = 180 ( sum of angles in a triangle )

6x + 72 = 180 ( subtract 72 from both sides )

6x = 108 ( divide both sides by 6 )

x = 18 → D

8 0
3 years ago
May you please help me with this​
Bad White [126]
It’s A I did it before trust me
7 0
3 years ago
Read 2 more answers
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