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3 years ago

15

Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim.

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

a) There is not sufficient evidence to support the claim that the mean attendance is greater than 642.

Step-by-step explanation:

since in the question it is mentioned that the average attendance at games should be more 642 and according to this he moving the team with a larger stadium. Also the hypothesis conducted and the conclusion would be failure to deny the null hypothesis

So here the conclusion that should be made in non-technical term is that there should be no enough proof in order to support the claim that the mean attendence is more than $642

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The sum of 3 consecutive integers is 45. Which equation represents this?

cestrela7 [59]

Consecutive integers are 1 apart
they are
x,x+1,x+2
so it would be
x+x+1+x+2=45
B is answer

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3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

<u>Finding P(A)</u>

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

<u>Finding P(B)</u>

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

<u>Finding $P(A \cap B)$ </u>

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

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3 years ago

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Brrunno [24]

Answer:

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Step-by-step explanation:

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3 years ago

Joey walked 10 laps around the school's track. He walked a total distance of 6.74 miles. Monica walked 30 laps around the same t

Anvisha [2.4K]

Answer:

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Step-by-step explanation:

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1 year ago

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Tems11 [23]

5x - y = -4 is the standard form

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4 years ago