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3 years ago

What is BD? please help

Mathematics

2 answers:

Alborosie3 years ago

6 0

I think you would set BC and CD equal to 180 bc BD is a straight line (180°). so x+5+x. you'd have 2x+5=180. once you get the x value, you'd plug it into the x+5 to get that length. i am not 100% about this though bc it does seem weird to have a decimal length..

astraxan [27]3 years ago

4 0

We’re looking for the angles right?

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4.8-2/5(w-6) mathematic equation

mixer [17]

Answer:

$\frac{0.56}{w - 6}$

Step-by-step explanation:

1) Simplify 4.8 - 2 to 2.8.

$\frac{2.8}{5(w - 6)}$

2) Simplify.

$\frac{0.56}{w - 6}$

Therefor, the answer is 0.56/w-6.

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3 years ago

Let Y1,Y2, . . . ,Yn be a random sample from a normal distribution where the mean is 2 and the variance is 4. How large must n b

Marina86 [1]

Answer:

n= 60

Step-by-step explanation:

Hello!

You have Y₁, Y₂, ..., Yₙ random sample with a normal distribution: Y~N(μ;σ²)

μ= 2

σ²= 4

You need to calculate a sample size n so that (1.9 ≤ Y ≤2.1)= 0.99

To reach the sample size you need to work with the distribution of the sample mean (Y[bar]) because it is this distribution that is directly affected by the sample size.

Y[bar]~N(μ;σ²/n)

Under the sample mean distribution you have to use the standard normal:

Z= Y[bar] - μ ~N(0;1)

σ/√n

Now the asked interval is:

P(1.9 ≤ Y[bar] ≤2.1)= 0.99

The upper bond is 2.1

The lower bond is 1.9

The difference between the two bonds is the amplitude of the interval a=2.1-1.9= 0.2

And the probability included between these two bonds is 0.99

With this in mind you can rewite it as an interval for the sample mean:

Y[bar] + $Z_{1-\alpha /2}$ *(σ/√n) - (Y[bar] + $Z_{1-\alpha /2}$ *(σ/√n))= 0.2

Using the semiamplitude (d) of the interval you can easly calculate the required sample:

d= a/2= 0.2/2= 0.1

d= $Z_{1-\alpha /2}$ *(σ/√n)

d* $Z_{1-\alpha /2}$ = σ/√n

√n*(d* [tex]Z_{1-\alpha /2}[/tex)= σ

√n= σ/(d* [tex]Z_{1-\alpha /2}[/tex)

n= (σ/(d* [tex]Z_{1-\alpha /2}[/tex))²

n= (2/(0.1* 2.586))²

n= 59,81 ≅ 60

I hope it helps!

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