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Viktor [21]
3 years ago
13

How to balance the equation NaNo3 + PbO & Pb(NO3)2 + Na2O

Physics
1 answer:
dedylja [7]3 years ago
6 0
It would be "Double replacement".

Hope this helps!
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A 2kg object is moving horizontally with a speed of 4 m/s. How much net force is required to keep the object moving at this spee
Elza [17]
We can solve this problem using the force equation.

Force = Mass * Acceleration

2kg * 4m/s = 8 N

The net force required to keep the object moving at this speed and in this direction is 8 N.


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a bungee jumper momentarily comes to rest at the bottom of the dive before he springs back upward. at that moment, is the bungee
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Answer:

Explanation:

No, the bungee jumper is not at equilibrium.

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4 years ago
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Jupiter's satellite Europa orbits Jupiter with a period of 3.55 d at an orbital radius of 6.71 108 m (assume the orbit to be cir
yawa3891 [41]

Answer:

(a)

M = 1.898 x 10^27 kg

(b)

v = 13.74 km/s

(c) E = 0.28 N/kg

Explanation:

Time period, T = 3.55 days = 3.55 x 24 x 3600 second = 306720 s

Radius, r = 6.71 x 10^8 m

G = 6.67 x 10^-11 Nm^2/kg^2

(a) T=2\pi \sqrt{\frac{r^{3}}{GM}}

M=\frac{4\pi ^{2}r^{3}}{GT^{2}}

M=\frac{4\times3.14^{2}\times 6.71^{3}\times 10^{24}}{6.67\times 10^{-11}\times 306720^{2}}

M = 1.898 x 10^27 kg

(b) Let v be the orbital velocity

v=\frac{2\pi r}{T}

v=\frac{2\times 3.14\times 6.71\times 10^{8}}{306720}

v = 13739.5 m/s

v = 13.74 km/s

(b) The gravitational field E is given by

E = \frac{GM}{r^{2}}

E = \frac{6.67\times10^{-11}\times 1.898\times 10^{27}}{6.71^{2}\times 10^{16}}

E = 0.28 N/kg

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