Answer:
Step-by-step explanation:
Let
A ----->Mr. Mole's altitude (in meters)
t ----> the time in minutes
we know that
Mr. Mole is descending at a constant rate, so we have a linear relationship
we have the points
For t=0 min, A=-7 m -----> point (0,-7) ----> A-intercept (value of A when the value of t is equal to zero)
For t=6 min, A=-16 m -----> point (6,-16)
<em>Find the slope of the linear equation</em>
Find the linear equation in slope intercept form
we have
substitute
Answer:
1. n=0 2. x = 15 and 3. m = -5
Step-by-step explanation:
1. 28^3*32^n = 28^3
Divide both sides by 28^3:-
32^n = 1
n = 0 ( any number to the power 0 = 1)
2. 30^x * 30^5 = 30^20
divide both sides by 30^5
30^x = 30^15
because the 2 bases are the same ( both = 390) we have:-
x = 15
3. a^m * a^3 = 1 / a^2
a^m * a^3 = a^-2
Divide both sides by a*3
a^m = a^-5
so m = -5
Answer:
$1.45
Step-by-step explanation:
7.25 divided by the 5 packs
7.25/5= $1.45 a pack
Answer:
134,850,000 so 135,000,000
Step-by-step explanation:
Answer:
The day would be 3.125 seconds longer in 25 centuries.
Step-by-step explanation:
Let's break it down.
Each year, 1250 microseconds are added to the planet's day.
We need to find how long a day would be in 25 centuries.
A century is 100 years.
A second is 1,000,000 microseconds.
The day would be 3.125 seconds longer in 25 centuries.