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Zigmanuir [339]
3 years ago
8

When should fixed and variable monthly budgeted expenses first be planned?

Mathematics
1 answer:
julsineya [31]3 years ago
8 0

Answer: At the star of each month

Step-by-step explanation:

Short-term financial goals might include buying movie tickets.

When creating a budget, you must track both your budgeted expenses and your … expenses. actual

When creating a budget, log fixed expenses after income.

When should fixed and variable monthly budgeted expenses first be planned? at the start of each month

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What are the vertex and xintercepts of the graph of the function below?<br> y=(x + 4)(x-2)
erik [133]

Yo sup??

y=(x+4)(x-2)

to find the x intercept put y=0

0=(x+4)(x-2)

so either x=-4 or x=2

Therefore the graph intersects the x axis at -4 and 2

Lenght of x intercept=|-4-2|=6 units

y=(x+4)(x-2)

=x^2+2x-8

This is an upward opening parabola

To find the coordinates of the vertex we can apply the formula

(-b/2a,-D/4a)

b=2

a=1

D=b^2-4ac

=4-4*1*(-8)

=4+32=36

Vertex=(-2/2*1,-36/4*1)

=(-1,-9)

Hope this helps.

3 0
3 years ago
2x^2 -7= 74 please show all work
skad [1K]
2x^2-7=74\\&#10;2x^2=81\\&#10;x^2=\dfrac{81}{2}\\&#10;x=-\sqrt{\dfrac{81}{2}} \vee x=\sqrt{\dfrac{81}{2}}\\&#10;x=-\dfrac{9}{\sqrt2} \vee x=\dfrac{9}{\sqrt2}}\\&#10;x=-\dfrac{9\sqrt2}{2} \vee x=\dfrac{9\sqrt2}{2}}\\
8 0
3 years ago
A painter uses the expression 35h + 30c to determine how much he charges a customer for a job that takes h hours and c cans of p
Savatey [412]

Answer:

c) $615

Step-by-step explanation:

The expression used to determine how much is the charge for the customer after the job is

p=35h+30c

where

h is the number of hours the job took

c is the number of cans of paint used during the job

In this problem:

c = 3 (the painter used 3 cans of paint)

h = 15 (the painter took 15 hours for the job)

So substituting these values into the equation for p, we find the total value that the painter charged for the job:

p=35\cdot 15 + 30 \cdot 3 =615

So, the correct answer is

c) $615

5 0
3 years ago
Find the real values of x and y <br> -4+3i-x+yi=8-6i
Marrrta [24]

Answer:

x = - 12, y = - 9

Step-by-step explanation:

Given

- 4 + 3i - x + yi = 8 - 6i

Simplify left side by collecting like terms and equate like coefficients with the terms on the right side, that is

- 4 - x + i(3 + y) = 8 - 6i, thus

3 + y = - 6 ( subtract 3 from both sides ) ← equating imaginary parts

y = - 9, then

- 4 - x = 8 ( add 4 from both sides ) ← equating real parts

- x = 12 ( multiply both sides by - 1 )

x = - 12

6 0
3 years ago
Please help and show step by step pls
Brut [27]

First notice that

<em>x</em> ² + 5<em>x</em> + 6 = (<em>x</em> + 3) (<em>x</em> + 2)

so you can rewrite everything with a common denominator:

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 / (<em>x</em> + 2) = 6 / (<em>x</em> + 3)

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / ((<em>x</em> + 2) (<em>x</em> + 3)) = 6 (<em>x</em> + 2) / ((<em>x</em> + 3) (<em>x</em> + 2))

5 / (<em>x</em> ² + 5<em>x</em> + 6) + 7 (<em>x</em> + 3) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

(5 + 7 (<em>x</em> + 3)) / (<em>x</em> ² + 5<em>x</em> + 6) = 6 (<em>x</em> + 2) / (<em>x</em> ² + 5<em>x</em> + 6)

As long as <em>x</em> ≠ -3 or <em>x</em> ≠ -2, the denominators are never zero, so we can cancel them and be left with

5 + 7 (<em>x</em> + 3) = 6 (<em>x</em> + 2)

Solving for <em>x</em> is easy from here:

5 + 7<em>x</em> + 21 = 6<em>x</em> + 12

7<em>x</em> - 6<em>x</em> = 12 - 5 - 21

<em>x</em> = -14

3 0
2 years ago
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