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REY [17]
3 years ago
11

NEED HELP ASAP PLEASE HELP

Mathematics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

the second one or b. :)

Step-by-step explanation:

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What is 1 5/8- 3/8 Express the answer in simplest form
Naddika [18.5K]
1 5/8 - 3/8 = 1 1/4

Subtract the numerators because the common denominators are the same and leave the whole number to make 1 2/8. To simplify it you divide it by 2 because that's the highest number that can go into both numerator and denominator to make is 1 1/4.

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3 years ago
Question 20 of 45<br> In right triangle ABC shown below, what is the length of AC ?
dimulka [17.4K]
In this question, you have to use the Pythagorean theorem. (the formula is in the box, ‘a squared’ and ‘b squared’ is used to find the legs of the triangle, while the ‘c squared’ in the formula is used to find the hypotenuse of the triangle.

5 0
3 years ago
Sarah's parents started a savings account for her when she was 12. The plan her parents chose earns 3.2% each year, and her pare
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Answer:

  $3846.87

Step-by-step explanation:

Assuming the interest is compounded annually, the value in 3 years is ...

  FV = P(1 +r)^t

  FV = $3500(1.032^3) ≈ $3846.87

Sarah's account will be worth about $3846.87.

5 0
4 years ago
Triangle RST was dilated by a scale factor of 1/2. The image, triangle R'S'T', is an isosceles triangle, with each leg measuring
maxonik [38]

Answer:

16 units

Step-by-step explanation:

RST was dilated by a scale factor of 1/2.  This means R'S'T' has sides that are 1/2 the length of the sides of RST.

Since the legs of R'S'T' are 8 units, this gives us the equation

8 = 1/2x

Divide both sides by 1/2:

8÷1/2 = x

8 × 2/1 = x

16 = x

Each leg in RST is 16 units.

3 0
4 years ago
Read 2 more answers
7. Verify the following: i) (ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0 ii) (a + b + c) (a² + b² + c² –
blsea [12.9K]

<u>1</u><u>.</u><u> </u><u>(ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0</u>

We know that (a+b)(a-b) = a²-b²

(ab + bc)(ab -bc) can be written as a²b² - b²c²

(bc + ca)(bc -ca) can be written as b²c² - c²a²

(ca + ab)(ca - ab) can be written as c²a² - a²b²

→ a²b² - b²c² + b²c² - c²a² + c²a² - a²b²

→ a²b² - a²b² - b²c² + b²c² - c²a² + c²a²

→ 0

<u>2</u><u>.</u><u> </u><u>(a + b + c) (a² + b² + c² – ab – bc – ca) = a³ + b³+ c³ – 3abc</u>

→ a³ + ab² + ac² -a²b - abc -ca² + a²b + b³ + bc² - ab² - b²c - abc + a²c + b²c + c³ - abc - bc² - c²a

→ a³ + b³+ c³ + (- abc - abc - abc) + (ab² - ab² )+ (ac² - ca² ) -(a²b + a²b )+ (bc² - bc² )+ (a²c - c²a) + (b²c - b²c)

→ a³+b³+c³ - 3 abc .

<u>3</u><u>.</u><u> </u><u>(p – q) (p² + pq + q²) = p³ – q³. </u>

→ p³ + p²q + pq² - p²q - pq² - q³

→ p³ - q³ +(p²q - p²q) + (pq² - pq²)

→ p³ - q³

7 0
4 years ago
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