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ELEN [110]
3 years ago
13

Please helppppppp :(((

Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

Answer:

its y = 1/2 x - 1

Step-by-step explanation:

why did math tutor delete my question?!?!??!

amid [387]3 years ago
4 0

Answer:

y = 1/2x - 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from the graph.</em>

x-intercept (2, 0)

y-intercept (0, -1)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-1-0}{0-2}
  2. Subtract:                       m=\frac{-1}{-2}
  3. Simplify:                        m=\frac{1}{2}

<u>Step 3: Write linear equation</u>

y = 1/2x - 1

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24/5 = (20 + 4)/5 = 20/5 + 4/5 = 4 + 4/5
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Two minor league baseball players got a total of 390 hits. Washington had 2 more hits than Sanchez. Find the number of hits for
Georgia [21]

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Answer:

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Step-by-step explanation:

Let s represent the number of hits Sanchez had. Then Washington had (s+2) hits, and their hit total was ...

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  2s = 388 . . . . . . subtract 2

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Sanchez had 194 hits; Washington had 196.

 

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3 years ago
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Step-by-step explanation:

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9^27=5.8149737e25

3 0
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3 years ago
lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.
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Answer with Step-by-step explanation:

Given

f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1

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3 years ago
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