1 : you would use a graduated cylinder . 2 : , you would use a yard stick or maybe a ruler if you are not able to find one. You can also use a meter stick.
Answer:
a) The percentage of athletes whose GPA more than 1.665 is 87.49%.
b) John's GPA is 3.645.
Step-by-step explanation:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a)Find the percentage of athletes whose GPA more than 1.665.
This is 1 subtracted by the pvalue of Z when X = 1.665. So



has a pvalue of 0.1251
1 - 0.1251 = 0.8749
The percentage of athletes whose GPA more than 1.665 is 87.49%.
b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.
His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.




John's GPA is 3.645.
Of I don’t know sorry about that
Answer:

Step-by-step explanation:
A quadratic in factored form is usually expressed as:
where the sign of a and b depends on the sign of the zero. And I said "usually" since sometimes the x will have a coefficient. Anyways in the quadratic there are two zeroes at x=-1 and x=3. This can be written as:
. Notice how the signs are different? This is because when you plug in -1 as x you get a factor of (-1+1) which becomes 0 and it makes the entire thing zero since when you multiply by 0, you get 0. Same thing for the x-3 if you plug in x=3. Now a is in front and it can influence the stretch/compression. To find the value of a, you can take any point (except for the zeroes, because it will make the entire thing zero, and you can technically input anything in as a)
I'll use the point (1, -4) the vertex
-4 = a(1+1)(1-3)
-4 = a(2)(-2)
-4 = -4a
1 = a. So yeah the value of a is 1
So the equation is just: 
Answer:
3x - 6
Step-by-step explanation:
To evaluate f(2x) and f(x + 2) substitute x = 2x and x = x + 2 into f(x)
f(2x) = 3(2x) - 2 = 6x - 2
f(x + 2) = 3(x + 2) - 2 = 3x + 6 - 2 = 3x + 4
Thus
f(2x) - f(x + 2)
= 6x - 2 - (3x + 4)
= 6x - 2 - 3x - 4
= 3x - 6