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3 years ago

Express the following as percentages. (i) 12 hours in 3 days

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

Answer:

16 2/3 %

Step-by-step explanation:

To put this in a percentage, they need to have the same units.

Let convert days to hours

1 day = 24 hours

Multiply by 3

3 days = 72 hours

The percentage is part over whole

12 hours / 72 hours

We can simplify by dividing top and bottom by 12

1/6

This is a fraction, change this to a decimal

.166666666

Now multiply by 100

16.666666 %

16 2/3 %

Zolol [24]3 years ago

6 0

Hope it helps you buddy

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Sara says that median does not have to be one of the numbers in a set.

VladimirAG [237]

Answer:

I think she is correct !

Step-by-step explanation:

3 0

3 years ago

Begin by clearly stating the problem; you can copy this from the problem set file. Show how you solved the problem step by step,

Y_Kistochka [10]

Answer: 13%

Step-by-step explanation:

The formula to find the simple interest is given by :-

$I=Prt$ , where P is the principal amount, r is rate of interest () in decimal and t is the time ( in years).

Given : P = $19,100 , I=$9932.00 and t= 4 years

Substitute all the above values in the formula , we get

$9932.00=(19100)r(4)\\\\\Rightarrow\ r=\dfrac{9932}{19100\times4}\\\\\Rightarrow r=\dfrac{13}{100}=0.13$

In percent , $r=0.13\times100=13\%$

Hence, the rate of interest = 13%

6 0

3 years ago

Which of the following geometric series converges?

Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is

$S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}$

Multiply both sides by r :

$rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n$

Subtract the latter sum from the first, which eliminates all but the first and last terms:

$S_n-rS_n=a-ar^n$

Solve for $S_n$ :

$(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}$

Then as gets arbitrarily large, the term $r^n$ will converge to 0, leaving us with

$S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}$

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0

3 years ago

Solve the following problems. I REALLY NEED HELP 80 POINTS!

lisabon 2012 [21]

Answer:

a 10 yd 2ft 7 in

b 10 yd 1 ft 2 in

c 99 yd

d. 4840 sq yd 7 sq ft 119 sq in

Step-by-step explanation:

a. 2 ft. 5 in. +

9 yd. 3 ft. 2 in.

---------------------

9 yd 5ft 7 in

but 3 ft = 1yd

9 yd 5ft 7 in

+1yd - 3ft

---------------------------

10 yd 2ft 7 in

b. 4 yd. 8 in

+ 6 yd. 6 in.

----------------------

10 yd 14 in

but 12 in = 1ft

10 yd 14 in

+ 1ft - 12 in

---------------------

10 yd 1 ft 2 in

c. 29 yd. 2 ft. 11 in.

55 yd. 1 ft. 10 in.

+ 13 yd. 1 ft. 3 in.

--------------------------

97 yd 4 ft 24 in

12 in = 1ft

24 in = 2ft

97 yd 4 ft 24 in

+2ft - 24 in

--------------------------------

97 yd 6ft

3 ft = 1yd

6f = 2yd

97 yd 6ft

+2yd - 6ft

---------------------

99 yd

d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.

+ 7 sq. ft. 124 sq. in.

--------------------------------------------------

4839 sq yd 15 sq ft 263 sq in

12*12 = 144 sq in = 1 sq ft

4839 sq yd 15 sq ft 263 sq in

+ 1 sq ft - 144 sq in

--------------------------------------------------

4839 sq yd 16 sq ft 119 sq in

3ft * 3 ft = 9 sq ft = 1 sq yd

4839 sq yd 16 sq ft 119 sq in

+1 sq yd - 9 sq ft

----------------------------------------------

4840 sq yd 7 sq ft 119 sq in

8 0

3 years ago

Read 2 more answers

What is the exact volume of the cone

Travka [436]

Answer:

V = $\frac{400}{3}$ $\pi$

Step-by-step explanation:

Volume of a cone is:

$V = \pi r^{2} \frac{h}{3}$

Substitute values given:

$V = \pi (5^{2} )(\frac{16}{3})$

$V = \pi (25)(\frac{16}{3} )$

V = $\pi \frac{400}{3}$

V = $\frac{400}{3}$ $\pi$

5 0

2 years ago