Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.
Answer:
p = 26
Q = 79
R =75
Step-by-step explanation:
because MNO is same as PQR (direction wise)
Answer:
choice number 2) 10 in, 18.5 in 31.5 in
Step-by-step explanation:
we collect and evaluate the like terms.like terms means the ones that can be evaluated. like 2y and 7y are like terms. they either can be added or subtracted to get an answer . 7y-2y =5y. but you cant subtrac or add 7y with 5 because they are not like terms.
2y +1 + 7y + 3y + 5 = 60
(2y+7y+3y)+(1+5) = 60
12y + 6 = 60
The 6 crosses the equal sign to the other side because of like terms.And becomes a minus
12y = 60 - 6
12y = 54
y = 4.5
so,
2y +1= 2 x 4.5 + 1 =10
7y = 7 x 4.5 = 31.5
3y + 5= 3 x 4.5 + 5 =18.5
Answer is 10 in, 18.5 in, 31.5 in
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120 * 45 % = 120 *0,45 = 54 £
120 -54 = 66 £
