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Pavlova-9 [17]
3 years ago
10

This is probably simple but can someone help me with this??

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

7.5 units

Step-by-step explanation:

First, create a proportion by picking 2 sides:

2.5/n = 5/15

Next, cross multiply:

5n = 37.5

Finally, divide both sides to isolate the variable:

7.5

Therefore your answer is 7.5 units.

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xz_007 [3.2K]

Answer:

9w + 3 = 6

Step-by-step explanation:

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If f(x) = x + 2 and g(x) = 3x +4, then (g °f)(x) = ?
Anastaziya [24]

The correct answer is a. 3x + 6

In order to find a compound function, you must use the first letter in the function (in this case f) and plug the second letter (g) in where you see x's.

f(x) = x + 2

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f(g(x)) = (3x + 4) + 2

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7 0
4 years ago
A chef cooked 5 kilograms of mashed potatoes for a dinner party. If the guests only ate 4/12 of the amount he cooked, how much d
balandron [24]

Answer:

1\frac{2}{3}\ kg

Step-by-step explanation:

we know that

To find out how much the guests ate, multiply the total amount of kg of mashed potatoes by the 4/12 fraction

so

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convert to mixed number

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4 0
3 years ago
Help me please help me please
4vir4ik [10]
Dividing means you subtract the exponents. Dividing by a number is the same as changing the sign on the exponent. 

x⁰/x² = x⁻² = 1/x²
y⁻³/y⁻¹ = y⁻³⁻⁻¹ = y⁻² = 1/y²

together is 1/x²y², answer B
6 0
3 years ago
The savings account offering which of these APRs and compounding periods offers the best APY?
ANTONII [103]
A)

\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
\left.  \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1196\%\to \frac{3.1196}{100}\to &0.031196\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left.  \qquad \qquad\right. \left(1+\frac{0.031196}{2}\right)^{2}-1

b)

\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
\left.  \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1184\%\to \frac{3.1184}{100}\to &0.031184\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four times}
\end{array}\to &4
\end{cases}
\\\\\\
\left.  \qquad \qquad\right. \left(1+\frac{0.031184}{4}\right)^{4}-1

c)

\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
\left.  \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1095\%\to \frac{3.1095}{100}\to &0.031095\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, assuming 365 days}
\end{array}\to &365
\end{cases}
\\\\\\
\left.  \qquad \qquad\right. \left(1+\frac{0.031095}{365}\right)^{365}-1

d)

\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
\left.  \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1172\%\to \frac{3.1172}{100}\to &0.031172\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve times}
\end{array}\to &12
\end{cases}
\\\\\\
\left.  \qquad \qquad\right. \left(1+\frac{0.031172}{12}\right)^{12}-1
8 0
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