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Svetach [21]
2 years ago
15

Find the value of x Hurry please

Mathematics
2 answers:
ki77a [65]2 years ago
7 0
This is definitely 12 the answer is 12 LOL
yulyashka [42]2 years ago
3 0

Answer:

In this case, the value of x would be 12. As you can see, all three sides are equal in lengths. So, as it shows all angles being equal, the sides will also be equal.

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Which is less, 8 ½ pounds or 130 ounces?
Harman [31]
Do you know how to convert pounds to ounces
3 0
2 years ago
Complete the diagram to find 430 percent of 90
ludmilkaskok [199]

The easiest way to find percent is to make the percent into a decimal and multiply. Move the decimal to places to the left to make 4.30, and multiplied by 90 equals 387, so 430 percent of 90 is 387.

3 0
3 years ago
NewPop produces their brand of soda drinks in a factory where they claim that the
Citrus2011 [14]

Answer:

a) 14960 bottles

b) 502 bottles

Step-by-step explanation:

Given that:

Mean (μ) = 24 ounces, standard deviation (σ) = 0.14 ounces

a) From empirical rule (68−95−99.7%) , 68% of the population fall within 1 standard deviation of the mean (μ ± 1σ).

Therefore 68% fall within 0.14 ounces of the mean

the number of bottle =  22,000*68% = 14960 bottles

b) To solve this we are going to use the z score equation given as:

z=\frac{x-\mu}{\sigma} where x is the raw score = 23.72

z=\frac{x-\mu}{\sigma}=\frac{23.72-24}{0.14} =-2

From the normal probability distribution table: P(X < 23.72) = P (Z < -2) = 0.0228

The number of rejected bottles = 22000 × 0.0228 = 502 bottles

8 0
3 years ago
In the figure below, EH GJ and FI intersects EH at G as shown below.
Pachacha [2.7K]

Answer:

D. 15°

Step-by-step explanation:

EGF and HGF are equal and 75°

since JGH is 90° we can say JGI is 90 - 75 = 15°

5 0
3 years ago
Help no time plzzzz plz plz​
Sav [38]

Answer:

FALSE

Step-by-step explanation:

<E in ∆AED ≅ <E in ∆CEB.

Both are 90°.

Side ED ≅ Side EB

Side AD ≅ Side CB.

Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.

8 0
3 years ago
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