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Rudiy27
3 years ago
11

The quantity y varies directly as x and inversely as z. When x is 10 and z is 4, y is 15. What is y when x is 20 and z is 6?

Mathematics
1 answer:
frosja888 [35]3 years ago
8 0
Y=(kx)/z


15=(k10)/4
15=(5k/2)
15=k(5/2)
ties both sides by 2/5 to clear fraction
6=k

y=(6x)/z

x=20
z=6
y=(6*20)/6
y=20
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Find out if the 3 positions are on the same line or not (3,2,0) (1, -1,2) (5,5, 2)
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The three positions are not on the same line.

Step-by-step explanation:

We have three points: A:(3,2,0),  B:(1,-1,2) and C:(5,5,2).

Let's build a vector that goes from one point to another; that vector will be the director of a line (if we draw a vector that goes from A to B, that vector will be the direction of the line that pass by A and B because it does not change). In order to build that vector, let's subtract B from A:

A-B=(3,2,0)-(1,-1,2)=(2,3,-2)

The equation of a line is:

p=p_0+rt

Where p is every singular point of the line, p_0 is a particular point of the line (any that we are sure that it is on the line), r is the director vector and t is the independent variable.

Now we have the director vector: (2,3,-2), and we can verify that A and B are on the line:

p=p_0+(2,3,-2)t

Because there is a value for t that satisfies both A and B: If we do p_0=(3,2,0) and t=0, we are going to obtain the point p=A; and if we do t=-1, we are going to obtain p=B. Let's see that:

p=(3,2,0)+(2,3,-2)*0=(3,2,0)\\p=A\\p=(3,2,0)+(2,3,-2)*-1=(1,-1,2)\\p=B\\

If C is also in the same line, C must accomplish the equation: p=(3,2,0)+(2,3,-2)t, so:

C=(5,5,2)=(3,2,0)+(2,3,-2)t

Let's simplify the equation writing the parametric equation, which is just to write the equation for each dimension:

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You can verify that there is not a value of t that satisfies all three equations, so, the point C is not on the same line as A and B; which means that A, B and C are not on the same line.

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