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Liula [17]
3 years ago
15

Timed Quiz! Please answer the question below for 50 points. It is very easy. 6th-grade math!

Mathematics
2 answers:
Rus_ich [418]3 years ago
3 0

Answer:

B is surely correct dude!

plz mark me as brainliest.

adell [148]3 years ago
3 0

Answer:

B.)

Step-by-step explanation:

Obviously, it is true.

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If the length of a rectangle is 3 feet less then twice its width and the area is 54square feet what are its dimensions
erma4kov [3.2K]
The length (L) of the rectangle can be written as a function of the width (W)L = 2W - 3:
Now since we know Area = Width*Length, we can write the area as a function of the width:
A = L*W = (2W-3)*W
Distributing the W inside the parentheses we have:
A = 2W^2 - 3W
We know the area is 54 ft^2, so we can rewrite it as:
2W^2 - 3W - 54 = 0
Now solve for W by factoring (or by applying the quadratic formula):
2W^2 - 12W + 9W - 54 = 0
Factor out a common 2W from the first two terms and a 9 from the last two terms:
2W(W-6) + 9(W-6) = 0
Regroup the terms to get our fully factored equation:
(2W + 9)(W-6) = 0
This gives us the roots W = 6 and W = -9/2, but width can't be negative so we have width = 6 ft. Then remember that the length L = 2W - 3, so our length is:
L = 2W - 3 = 2(6) - 3 = 12 - 3 = 9
So now we know that our rectangle is 9 feet long and 6 feet wide.
5 0
4 years ago
Simplify and find any restrictions<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B9x%7D%20-%5Cfrac%7B6%7D%7B2x%5E2%7D" i
Yuki888 [10]

Simplified: \frac{4}{9x} -\frac{3}{x^{2} }

Restrictions: x CANNOT be 0 because then the denominator would become 0 and would not be possible

5 0
3 years ago
Really need help on this guys!
Sergio039 [100]
<h2>Hello!</h2>

The answer is:

The center of the circle is the point (-9,-2) and the circle has a radius of 6 units.

<h2>Why?</h2>

To solve the problem, we need to use the given equation which is in the general form, and then, use it transform it to the standard form in order to find the center of the circle and its radius.

So,

We are given the circle:

x^{2}+y^{2}+18x+4y+49=0

We know that a circle can be written in the following form:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

h is the x-coordinate of the center of the circle

k is the y-coordinate of the center of the circle

r is the radius of the circle.

So, to find the center and the radius, we need to perform the following steps:

- Moving the constant to the other side of the equation:

x^{2}+y^{2}+18x+4y=-49

- Grouping the terms (x and y):

x^{2}+18x+y^{2}+4y=-49

- Completing squares for both variables, we have:

We need to sum to each side of the equation the following term:

(\frac{b}{2})^{2}

Where, b, for this case, will the coefficients for both terms that have linear variables (x and y)

So, the variable "x", we have:

x^{2} +18x

Where,

b=18

Then,

(\frac{18}{2})^{2}=(9)^{2}=81

So, we need to add the number 81 to each side of the circle equation.

Now, for the variable "y", we have:

y^{2} +4y

Where,

b=4

(\frac{4}{2})^{2}=(2)^{2}=4

So, we need to add the number 4 to each side of the circle equation.

Therefore, we have:

(x^{2}+18x+81)+(y^{2}+4y+4)=-49+81+4

Then, factoring, we have that the expression will be:

(x+9)^{2}+(y+2)^{2}=36

- Writing the standard form of the circle:

Now,  from the simplified expression (after factoring), we can write the circle in the standard form:

(x+9)^{2}+(y+2)^{2}=36

Is also equal to:

(x-(-9))^{2}+(y-(-2))^{2}=36

Where,

h=-9\\k=-2\\r=\sqrt{36}=6

Hence, the center of the circle is the point (-9,-2) and the circle has a radius of 6 units.

Have a nice day!

4 0
4 years ago
How many solutions are there to the equation below? 17 x - 8 = 3x + 16<br>maqth ​
vazorg [7]

Answer:

There is one solution and that answer is mixed number form  1 5/7 or exact form 12/7

Step-by-step explanation:

8 0
3 years ago
Write three expressions that are equivalent to 3x + 15
shusha [124]
3(x+5)
5x+10-2x+5
15+3x
5 0
3 years ago
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