◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
Answer:
First, let's address the general case.
When we have two points (a,b) and (c,d)
The distance between those points can be written as:
D = √( (a - c)^2 + (b - d)^2)
In this case, the points are:
(-2,4) and (2,4)
Then the distance is:
D = √( (-2 - 2)^2 + (4 - 4)^2) = √(-4)^2 = 4.
The equivalent expression to this is: |-2| + |2|
because:
I-2I = 2
I2I = 2
I-2I + I2I = 2 + 2 = 4.
51 Divide what's in the ( ) then add the 3
