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3 years ago

Find the sum 6Y a +7Ya

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer:

13Ya is the answers for the question

Step-by-step explanation:

please mark me as brainlest

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Select the correct answer. A model rocket was launched from the top of a building. The rocket's approximate height can be modele

garri49 [273]

Answer:

13 seconds.

Step-by-step explanation:

Given

$h = -4.9(t - 13)(t + 2).$

Required

Determine a reasonable solution for t

To do this, we equate h to 0.

$h = -4.9(t - 13)(t + 2).$ becomes

$0 = -4.9(t - 13)(t + 2).$

Divide through by -4.9

$0 = (t - 13)(t + 2).$

Reorder the expression

$(t - 13)(t + 2) = 0.$

Split

$t-13 = 0$ or $t + 2 = 0$

This gives:

$t = 13$ or $t = -2$

But time can't be negative, So:

$t = 13$

6 0

3 years ago

A = 7x2 - 3x + 10

Whitepunk [10]

Answer:

A - B = 11x² -9x + 14

5 0

3 years ago

The average allowsnce money of Ernest jack David and mike is 123 per month per person. The average allowance of Ernest jack and

Evgesh-ka [11]

Answer:

Ernest gets 194 monthly allowance

Step-by-step explanation:

* Lets revise the rule of the average

- Average = The sum ÷ the total number

- Assume that the allowances money of Ernest, Jack, David and Mike

are E, J, D, M respectively

∵ The average allowance money of Ernest jack David and mike is

123 per month per person

∴ 123 = (E + J + D + M) ÷ 4

- Multiply both sides by 4

∴ E + J + D + M = 492 ⇒ (1)

∵ The average allowance of Ernest jack and David is 159 per month

per person

∴ 159 = (E + J + D) ÷ 3

- Multiply both sides by 3

∴ E + J + D = 477 ⇒ (2)

- Subtract equation(2) from equation (1) to find M

∴ M = 15

* Mike's monthly allowance is 15

∵ David's monthly allowance is 2 less than mikes

∴ D = M - 2

∵ M = 15

∴ D = 15 - 2 = 13

∴ David's monthly allowance is 13

∵ Mikes monthly allowance is 1/18 of jacks

∴ M = $\frac{1}{18}$ × J

∴ 15 = $\frac{1}{18}$ × J

- Multiply both sides by 18

∴ J = 270

* Jack's monthly allowance is 270

- Substitute the values of D , J in equation (2) to find E

∵ D = 13 and J = 270

∵ E + J + D = 477

∴ E + 270 + 13 = 477

∴ E + 283 = 477

- Subtract 283 from both sides

∴ E = 194

* Ernest's monthly allowance is 194

* Ernest gets 194 monthly allowance

4 0

3 years ago

What is the value of x? 799 A. 36° B. 14° C. 1440 D. 56

Alborosie

Option A because the whole triangle equals 180 degrees so as long as your option plus the numbers in the triangle equal 180° you will get it right

8 0

3 years ago

You’ve bought a half-dozen (six) eggs from the store but you forgot to check them first! The probability that no eggs are broken

GREYUIT [131]

Answer:

$P(X = 0) = C_{6,0}.(0.1416)^{0}.(0.8584)^{6} = 0.4$

$P(X = 1) = C_{6,1}.(0.1416)^{1}.(8584)^{5} = 0.3960$

$P(X = 2) = C_{6,2}.(0.1416)^{2}.(8584)^{4} = 0.1633$

$P(X = 3) = C_{6,3}.(0.1416)^{3}.(8584)^{3} = 0.0359$

$P(X = 4) = C_{6,4}.(0.1416)^{4}.(8584)^{2} = 0.0044$

$P(X = 5) = C_{6,5}.(0.1416)^{5}.(8584)^{1} = 0.0003$

$P(X = 6) = C_{6,6}.(0.1416)^{6}.(8584)^{0} = 0.00001$

b) 56.77% probability that an even number of eggs is broken.

Expectation: 0.8496

Variance: 0.7293

Step-by-step explanation:

For each egg, there are only two possible outcomes. Either it is broken, or it is not. The probability of an egg being broken is independent from other eggs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The variance of the binomial distribution is:

$V(X) = np(1-p)$

There are 6 eggs

So $n = 6$

The probability that no eggs are broken is 0.4.

This means that $P(X = 0) = 0.4$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.p^{0}.(1-p)^{6}$

$(1 - p)^{6} = 0.4$

Taking the sixth root from both sides of the equality

$(1 - p) = 0.8584$

p = 0.1416

Each egg has a 0.1416 probability of being broken

(a) Write out the pmf of X.

Probability of each value, from 0 to 6

$P(X = 0) = C_{6,0}.(0.1416)^{0}.(0.8584)^{6} = 0.4$

$P(X = 1) = C_{6,1}.(0.1416)^{1}.(8584)^{5} = 0.3960$

$P(X = 2) = C_{6,2}.(0.1416)^{2}.(8584)^{4} = 0.1633$

$P(X = 3) = C_{6,3}.(0.1416)^{3}.(8584)^{3} = 0.0359$

$P(X = 4) = C_{6,4}.(0.1416)^{4}.(8584)^{2} = 0.0044$

$P(X = 5) = C_{6,5}.(0.1416)^{5}.(8584)^{1} = 0.0003$

$P(X = 6) = C_{6,6}.(0.1416)^{6}.(8584)^{0} = 0.00001$

(b) Compute the probability that an even number of eggs is broken.

0, 2, 4 or 6

$P = P(X = 0) + P(X = 2) + P(X = 4) + P(X = 6) = 0.4 + 0.1633 + 0.0044 + 0.00001 = 0.5677$

56.77% probability that an even number of eggs is broken.

(c) Compute the expectation and variance of X.

Expectation:

$E(X) = np = 6*0.1416 = 0.8496$

Variance:

$V(X) = np(1-p) = 6*0.1416*0.8584 = 0.7293$

7 0

4 years ago