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Pani-rosa [81]
3 years ago
7

Can someone pleaseeee help if you’re correct I’ll give u brainlist

Mathematics
1 answer:
Ratling [72]3 years ago
7 0

Answer:

I haven't learn that yet but you can try asking desmos that app or web may help you with your question!

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Did I do this right????
Svetlanka [38]

Answer:

x = -7, y = -3 yup you did it right!

Step-by-step explanation:

Solve the following system:

{-2 y + x = -1 | (equation 1)

8 y - 5 x = 11 | (equation 2)

Swap equation 1 with equation 2:

{-(5 x) + 8 y = 11 | (equation 1)

x - 2 y = -1 | (equation 2)

Add 1/5 × (equation 1) to equation 2:

{-(5 x) + 8 y = 11 | (equation 1)

0 x - (2 y)/5 = 6/5 | (equation 2)

Multiply equation 2 by 5/2:

{-(5 x) + 8 y = 11 | (equation 1)

0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:

{-(5 x) + 8 y = 11 | (equation 1)

0 x + y = -3 | (equation 2)

Subtract 8 × (equation 2) from equation 1:

{-(5 x) + 0 y = 35 | (equation 1)

0 x + y = -3 | (equation 2)

Divide equation 1 by -5:

{x + 0 y = -7 | (equation 1)

0 x + y = -3 | (equation 2)

Collect results:

Answer: {x = -7, y = -3

4 0
2 years ago
The rectangular floor of a classroom is 32 feet in length and 36 feet in width. A scale drawing of the floor has a length of 8 i
Vanyuwa [196]

Answer:

34

Step-by-step explanation:

32 / 8 = 4
36 / 4 = 9

perimeter of rectangle = 2(Length) + 2(width)
P = 2(8) + 2(9)
P = 16 + 18
P = 34

6 0
2 years ago
Jon is launching rockets in an open field. The path of the rocket can be modeled by the quadratic function h(t) = -16t^2 + 96t,
IrinaVladis [17]
It will reach 80 feet for the second time after 5 seconds.

We set the equation equal to 80 feet:
80= -16t² + 96t

When solving quadratics, we want it equal to 0, so we subtract 80 from both sides:
80-80= -16t² + 96t - 80
0= -16t² + 96t - 80

We use the quadratic formula to solve:
t=\frac{-96\pm \sqrt{96^2-4(-16)(-80)}}{2(-16)}
\\
\\t=\frac{-96\pm \sqrt{9216-5120}}{-32}
\\
\\t=\frac{-96\pm \sqrt{4096}}{-32}
\\
\\t=\frac{-96\pm 64}{-32}
\\
\\t=\frac{-96+64}{-32} \text{ or } 0=\frac{-96-64}{-32}
\\
\\t=1 \text{ or } t=5
4 0
4 years ago
If -4 is a root of the equation x^2+px-4=0 and the equation x^2+px+q=0 has equal roots, find the value of p and q
zubka84 [21]

Answer:

p = 3, q = 2.5

Step-by-step explanation:

Given that x = - 4 is a root of the equation, then

(- 4)² - 4p - 4 = 0, that is

16 - 4p - 4 = 0

12 - 4p = 0 ( subtract 12 from both sides )

- 4p = - 12 ( divide both sides by - 4 )

p = 3

Also given that the equation x² + px + q = 0 has equal roots

Thus the value of the discriminant b² - 4ac = 0

Here a = 1, b = p and c = q, thus

p² - 4q = 0 ← substitute p = 3 from above into the equation

9 - 4q = 0 ( subtract 9 from both sides )

- 4q = - 9 ( divide both sides by - 4 )

q = 2.5

8 0
4 years ago
Algebra question please help
Oksana_A [137]

D. 15s +80t less than or equal to 4

hope that this helped you hon :)

4 0
3 years ago
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