A hamburger costs $2.5 and a milkshake costs $1.75
Step-by-step explanation:
- Step 1: Form equations from the given details. Let cost of 1 hamburger be H and cost of 1 milkshake be M.
4H + 2M = 13.50 ------ (1)
& 3H + 1M = 9.25 ------ (2)
- Step 2: Multiply eq(2) with 2 to make coefficients of M equal.
6H + 2M = 18.50 ------- (3)
- Step 3: Subtract eq(3) from eq(1)
⇒ - 2H = - 5
⇒ H = $2.5
- Step 4: Substitute value of H in eq(2) to find M.
⇒ 3 × 2.5 + M = 9.25
⇒ 7.5 + M = 9.25
⇒ M = $1.75
Answer:
-6.205
Step-by-step explanation:
The find the equation of a line in any form, you will have to find out the slope first:
m=(y2-y1)/(x2-x1)=(48-12)/(32-34)=-18
the simplified form is the slope-intercept form, so next we need to find the y intercept,
y=mx+b =>y=-18x+b
Use any of the two given points to find out b: 12=-18(34)+b =>b=624
so the equation is: y=-18x +624
Please double check the calculation by yourself
Answer:
E(x) = -7
Step-by-step explanation:
This is middle school math? It uses some advanced statistics
E(x) = 
E(x) = -7
Bill should not play the game as he will lose money on average
If Bill owns the game, he should play it as it would be an effective way to launder money
Answer:
At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The red ant's distance from the anthill is
. The black ant's coordinates may be written as (-a, -a) and the black ant's distance from the anthill is
. This shows that at any given moment, both ants are
units from the anthill.
Step-by-step explanation:
Given:
red ant's coordinates written as (a,a)
black ant's coordinates are written as (-a, -a)
To find:
The distance of red and black ants from anthill
Solution:
Compute the distance of red ant from the anthill using distance formula
d (red ant) = 
= 
= 
=
So distance of red ant from anthill is
Compute the distance of black ant from the anthill using distance formula
d (black ant) = 
= 
= 
= 
=
So distance of black ant from anthill is
Hence both ants are
units from the anthill.