Answer:
Step-by-step explanation:
If you would like me to explain let me know in the comments.
I need the measurement of angle a
1 answer:
<h2><u>Given</u>:-</h2>
Angle B = 90°
Angle C = 67°
<h2><u>To</u> <u>find</u>:-</h2>Angle A.
<h2><u>Solution</u>:-</h2>✅
We know that,
➪ ∠ A + ∠ B + ∠ C = 180°
➪ ∠ A + 90° + 67° = 180°
➪ ∠ A + 157° = 180°
➪ ∠ A = 180° - 157°
➪ ∠ A = 23°
∠ A + ∠ B + ∠ C = 180°
✒ 23° + 90° + 67° = 180°
✒ 180° = 180°
✒ L. H. S. = R. H. S.
<u>Note</u>:-
Please refer to the attached file.
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Answer:
The length of BC is needed because it is the side opposite ∠A.
Step-by-step explanation:
Given the right angles triangle as shown in the attachment, we can get sin(A) without using Pythagoras theorem. Instead we will use SOH CAH TOA trigonometry identity.
According to SOH:
Sin(A) = Opposite/Hypotenuse
Sin(A) = |BC|/|AB|
Opposite side of the triangle is the side facing ∠A.
Based on the formula, we will need to get the opposite side of the triangle which is length BC for us to be able to determine sinA since the hypotenuse is given.
*see attachment for the figure described
Answer:
5 units
Step-by-step explanation:
==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
Area of kite = ½ × d1 × d2
Where d1 = KH = 7
d2 = EG = KE + KG = x + x = 2x
Area of kite EFGH = 35
THUS:
35 = ½ × 7 × 2x
35 = 1 × 7 × x
35 = 7x
Divide both sides by 7
35/7 = x
x = 5
