Answer:
There are two solutions for x;
x = 0
x = 
Step-by-step explanation:
Let's try to divide the sentence into multiple parts and then combine it one by one to make it easier to understand.
1. True
2 times y and 6 -------->(2y+6)
the square of the sum of "2 times y and 6" -------->(2y+6)^2
8 times "the square of the sum of 2 times y and 6"------> 8(2y+6)^2
2. True
the difference of x and 7 -------->(x-7)
9 and x -------->(9 + x)
2 times the product of the sum of
"9 and x" and "the difference of x and 7"-------> 2(9 + x) (x-7)
3. True
difference of 5 times x and 3 -------->(5x-3)
the square of the difference of 5 times x and 3------->(5x-3)^2
4. False
The description should be: the product of 7 and the square of x
the product of 7 and x -------->(7x)
the square of the product of 7 and x -------->(7x)^2
5. True
This one should be clear as it was one sentences
the sum of y squared(y^2) and three times y(3y) minus 4-------->y^2+ 3y -4
6. False
The description should be: the product of 5 and 8 times the square of x plus the sum of 20x and 8
the sum of 20x and 8 -------->20x+8
8 plus the square of x plus the sum of 20x and 8-------->8+ x^2 +20x+8
the product of 5 and.... ------->(5)(........
the product of 5 and
8 plus the square of x plus the sum of 20x and 8---->(5)(8+ x^2 +20x+8)
Answer:
Step-by-step explanation:
Second one is faster, so let's get rid of it first.
Divide by 2 to make numbers easier, and we get
. You should recognize 81 is 9 squared, and both 
and 
, when squared, give 81, we have our solution.
Now the first. I can't spot any quick trick to solve it, so quadratic formula it is. Let's rememer it: if
then
Let's bring the first equation in the standard form and calculate the quantity over the square root (usually called with the greek letter delta, 
) to the side.
now we can apply the formula:
Let's split the two cases now
Answer:
It should equal zero or seven. I think is zero
X intercept: y = 0
y= -3/4x -4
0 = -3/4 x - 4
4= -3/4 x
4 • -4/3 = x
-5.3 = x
y intercept: x = 0
y = -3/4 x -4
y = -3/4 (0) -4
y = -4
the points are (-5.3, 0) and (0, -4)
