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2 years ago

Helllp pleaseeee!!!! Solve for x. 2^4x=8^3x-10

Mathematics

2 answers:

Karolina [17]2 years ago

5 0

Answer:

x=6

Step-by-step explanation:

igomit [66]2 years ago

4 0

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

(24)(x)=(83)(x)−10

Step 1: Simplify both sides of the equation.

(24)(x)=(83)(x)−10

16x=512x+−10

16x=512x−10

Step 2: Subtract 512x from both sides.

16x−512x=512x−10−512x

−496x=−10

Step 3: Divide both sides by -496.

−496x

−496

−10

−496

248

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Whats next two terms for 1, 2, 0, 3, -1

Masteriza [31]

Answer:

4, -2

Step-by-step explanation:

1+1=2

2-2=0

0+3=3

so on

+1,-2,+3,-4,+5,-6...

7 0

3 years ago

How do you find the volume of the solid generated by revolving the region bounded by the graphs

d1i1m1o1n [39]

Answer:

About the x axis

$V = 4\pi[ \frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

Step-by-step explanation:

For this case we have the following functions:

$y = 2x^2 , y=0, X=2$

About the x axis

Our zone of interest is on the figure attached, we see that the limit son x are from 0 to 2 and on y from 0 to 8.

We can find the area like this:

$A = \pi r^2 = \pi (2x^2)^2 = 4 \pi x^4$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= 4\pi \int_{0}^2 x^4 dx$

$V = 4\pi [\frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

For this case we need to find the function in terms of x like this:

$x^2 = \frac{y}{2}$

$x = \pm \sqrt{\frac{y}{2}}$ but on this case we are just interested on the + part $x=\sqrt{\frac{y}{2}}$ as we can see on the second figure attached.

We can find the area like this:

$A = \pi r^2 = \pi (2-\sqrt{\frac{y}{2}})^2 = \pi (4 -2y +\frac{y^2}{4})$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \pi \int_{0}^8 2-2y +\frac{y^2}{4} dy$

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

The figure 3 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (8-2x^2)^2 = \pi (64 -32x^2 +4x^4)$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= \pi \int_{0}^2 64-32x^2 +4x^4 dx$

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

The figure 4 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (\sqrt{\frac{y}{2}})^2 = \pi\frac{y}{2}$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \frac{\pi}{2} \int_{0}^8 y dy$

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

6 0

3 years ago

Can someone pls tell me if this is right? if its not then what is the right answer?

noname [10]

Answer:

It's right :)

Explanation:

Dilation along the x-axis = (-7-1)/(-1-1) = 2/8 = 1/4
Dilation along the y-axis = (-7-1)/(-1-1) = 2/8 = 1/4

Thus, the overall dilation is 1/4

3 0

2 years ago

Read 2 more answers

Dario divides 4/6 yard of rope equally into 1/12 yard pieces for a craft project.How many pieces of rope does Dario have?Use a n

zubka84 [21]

Answer:

Eight pieces

Step-by-step explanation:

Create a number line running from 0 to 4/6.

Label the divisions as 1/6, 2/6, 3/6, and 4/6.

Divide each section in half to get small pieces of length 1/12.

Starting at zero, move to 4/6 on the number line and count the number of pieces as you go.

You count eight pieces, so Dario has eight pieces of rope.

5 0

3 years ago

Read 2 more answers

While unpacking a box of canned vegetables, you notice that 2 out of 40 cans are dented. Write “2 out of 40” as a fraction, deci

nata0808 [166]

2/40=1/20
Percentage:5%
Decimal-0.05

8 0

2 years ago