Solve the system by substitution. 5x+y=−17 −3x−3y=3

Every kid in Mr. Levans's 3rd grade class made a valentine for every kid in the class, including him- or herself. If the class m

Assoli18 [71]

I would say 22 i first looked at amount of average kids in a class then tried every number close. 484/22=22

3 0

3 years ago

Read 2 more answers

Enzo is driving to his niece's t-ball game. his sister gave him directions. what will

just olya [345]

The direction given by Enzo's sister is an illustration of distance

Enzo's distance from the east of 1st avenue to the field is 6 miles

<h3>How to describe the directions?</h3>

From the question, we have the following directions:

Start at east of 1st avenue
Drive 3 miles
Make a 90 degrees right turn
Drive 1 mile
Turn at 90 degrees intersection
Drive 2 miles

The above directions imply that the total distance from the east of 1st avenue to the field is:

Distance = 3 miles + 1 mile + 2 miles

Evaluate the sum

Distance = 6 miles

Hence, Enzo's distance from the east of 1st avenue to the field is 6 miles

Read more about distance at:

brainly.com/question/4931057

6 0

2 years ago

Read 2 more answers

A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d

Alenkasestr [34]

Answer:

μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

Distance 1:

- Ff*d₁ = Ef - Ei

⇒ - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ

⇒ - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ (I)

Distance 2:

- Ff*d₂ = Ef - Ei

⇒ - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒ μ*g*d₂ = 0.5*v² (II)

If we apply (I) + (II)

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ (III)

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁ ⇒ vf² = 2*g*Sin θ*d₁ = v²

then (from the equation III) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒ μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒ μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK ⇒ - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁ ⇒ d₂ = Sin θ*d₁ / μ

3 0

4 years ago

Prove the polynomial identity.

Kaylis [27]

Answer:

Proven

Step-by-step explanation:

We prove the polynomial with factorization. We must first simplify the expression before we can factorize:

$(4\cdot{x^2}-2)\cdot{(4\cdot{x^2}-2)}-16\cdot{x^4}$

$16\cdot{x^4}-8\cdot{x^2}-8\cdot{x^2}+4-16\cdot{x^4}$

$4-16\cdot{x^2}$

4 is the common number and we can take it out of the expression:

$4\cdot{(1-4\cdot{x^2})}$

We can factorize further with the x term being zero. For this to be true we must have -2x and 2x to cancel out and therefore the expression is proven:

$4\cdot{(1-2\cdot{x})}\cdot{(1+2\cdot{x})}$

5 0

3 years ago

Is a parallelogram a square. JUST SAY YES OR NO, SKIP THE EXPLANATION

allochka39001 [22]

Answer:

no

You said skip the explanation, so ok

6 0

3 years ago