The surface area (SA) of a cube can be written as:
SA = 6s²
From here we can write, the length of the side s as:
![s= \sqrt{ \frac{SA}{6} }](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B%20%5Cfrac%7BSA%7D%7B6%7D%20%7D%20)
For cube with surface area of 1200 square inches, the side length will be:
![s= \sqrt{ \frac{1200}{6} }=10 \sqrt{2}](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B%20%5Cfrac%7B1200%7D%7B6%7D%20%7D%3D10%20%5Csqrt%7B2%7D%20%20)
inches
For cube with surface area 768 square inches, the side length will be:
![s= \sqrt{ \frac{768}{6} }=8 \sqrt{2}](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B%20%5Cfrac%7B768%7D%7B6%7D%20%7D%3D8%20%5Csqrt%7B2%7D%20)
inches
The difference in side lengths of two cubes will be:
Rounding to nearest tenth of an integer, the difference between the side lengths of two cubes will be 2.8 inches.
The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².
<h3>How to derive the equation of the parabola from the locations of the vertex and focus</h3>
Herein we have the case of a parabola whose axis of symmetry is parallel to the x-axis. The <em>standard</em> form of the equation of this parabola is shown below:
(x - h) = [1 / (4 · p)] · (y - k)² (1)
Where:
- (h, k) - Coordinates of the vertex.
- p - Distance from the vertex to the focus.
The distance from the vertex to the focus is 1 / 8. If we know that the location of the vertex is (0, 0), then the <em>standard</em> form of the equation of the parabola is:
x = 2 · y² (1)
The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².
To learn more on parabolae: brainly.com/question/4074088
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Answer:
the shortest route is from cabin site to B
Step-by-step explanation:
see my attachment
The ratio of linear dimensions (side lengths) is the square root of the ratio of areas.
√1 : √4 = 1 : 2
The best choice is ...
B. 1:2