Events:
1 ≤ n ≤ 100
A=x is a perfect square, i.e. x=n^2
B=x is odd, i.e. n is odd
P(A|B)
=P(A∩B)/P(B) by definition of conditional probability
(reads Probability that the number is a perfect square given that it is odd)
Since there are 10 perfect squares between 1 to 100 (1,4,9,16,25,36,49,64,81,100), out of which 5 are odd {1,9,25,49,81)
So P(A∩B)=5/100
P(B)=probability of odd x {1,3,5,7,.....95,97,99}
= 50/100=1/2
Therefore
P(A|B)=(5/100)/(1/2)=1/10
Step-by-step explanation:
Well, Let's find out!
Gloria says,
2(3x+6)-9x=3*4
By using distributive law
6x+12-9x=12
12-3x=12
-3x=12-12
-3x=0
x=0/-3
So she is not correct
Answer:
ntersecting lines DA and CE.
To find:
Each pair of adjacent angles and vertical angles.
Solution:
Adjacent angles are in the same straight line.
Pair of adjacent angles:
(1) ∠EBD and ∠DBC
(2) ∠DBC and ∠CBA
(3) ∠CBA and ∠ABE
(4) ∠ABE and ∠EBD
Vertical angles are opposite angles in the same vertex.
Pair of vertical angles:
(1) ∠EBD and ∠CBA
(2) ∠DBC and ∠EBA
33.33? im not sure, but you do a/b=p/100. p is the percent, a is the part of the whole number, b. so the equation would be 20/b=60/100. then you do cross multiplication (60b=2000) then you divide.
Step-by-step explanation:
your welcome
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