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inessss [21]
3 years ago
5

Will list you brainlest please hurry

Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0

Answer:

0- -3 1/4+1 3/4

Step-by-step explanation:

i belive this is the answer, but im not 100% sure sry if im wrong

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Which expression is equivalent to 5.4+3.4w-1.8w +5.8 A) 7(1.6+w) B) 1.6(7+w) C) 1.6(7w) D) 1.6(0.25+w)
Bad White [126]
Do 5.4 plus 5.8 then do 3.4w minus 1.8w and whatever you get for each is your key to the expression. So if you were to solve the answers like A you would do 7(1.6+w) and see what you would get. Obviously A isn't the answer. Sorry, this is hard to explain. But the answer is C 
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4 years ago
Solve for y in the given equation 2y - 24 = 14y <br> Answer are <br><br> 8y <br> -8y<br> -2 <br> 2
ArbitrLikvidat [17]

Answer:

y = -2

Step-by-step explanation:

First, we subtract 2y on both sides:

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Then, we divide 12 on both sides:

y = -2

And we're done ^^ hope this helps!

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4 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
The area of a rectangular pool is 6992 m².
Nina [5.8K]

Step-by-step explanation:

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length=92m

Now,

area of rectangle=6992

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3 years ago
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