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Georgia [21]
3 years ago
10

Find the zeroes of the function f(x). f(x)=(x–3)(x+4)

Mathematics
1 answer:
Ymorist [56]3 years ago
5 0

Answer:Set \displaystyle f\left(x\right)=0f(x)=0.

Step-by-step explanation:

Set \displaystyle f\left(x\right)=0f(x)=0.

If the polynomial function is not given in factored form:

Factor out any common monomial factors.

Factor any factorable binomials or trinomials.

Set each factor equal to zero and solve to find the \displaystyle x\text{-}x- intercepts.

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Locate the point (-3.5, -1) on the coordinate plane:
MrRissso [65]

Answer:

go to the left 3.5 units then go down one and that's your point

8 0
3 years ago
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Only blue and white vans are made at a factory. The ratio of the number of blue vans to the number of white vans is 4 : 3 write
amid [387]

Answer:

4/7

Step-by-step explanation:

Number of Blue vans = 4

Number of white vans = 3

Total number of vans = Number of Blue vans + Number of white vans

= 4 + 3

= 7 vans

Number of blue vans : Number of white vans = 4 : 3

Fraction of vans that are blue = Number of Blue vans / Total number of vans

= 4 / 7

Fraction of vans that are blue = 4/7

7 0
3 years ago
Complete the proof for proving that the diagonals of an isosceles trapezoid are congruent.
Alina [70]
..............................[a+b]2+c2
4 0
3 years ago
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
James has 36 tulips. He must put the same number of tulips in each vase. How many tulips could be in each vase
k0ka [10]
1,2,3,4,6,9,12,18,36



please can i have a brainliest

7 0
4 years ago
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